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Ronch [10]
4 years ago
5

Complete the inequality. 11 gal ___ 28 qt > < =

Mathematics
1 answer:
Sveta_85 [38]4 years ago
7 0
11 gal is more than (>) 28qt
You might be interested in
I need help plz, i dont understand :(
dedylja [7]

Answer:

Step-by-step explanation:

follow a few exponent rules and you can figure this out

when expoenents are to the power of something you can mutilply the expoents.. and when there is a minus sign in the exponent.. it's like the reciprocal   x^{-2}  is  1/x^{2}    soooo...

mutilply the  -2/3 by each of the exponents in the question the 8 is tricky b/c it has an invisible 1 on it :o

= 8^{-2/3}w^{-14/3}x^{10/3}y^{-6/3}z^{18/3}

= 1/\sqrt[3]{8*8} * 1/w^{14/3} * x^{10/3} * 1/y^{2} * z^{6}

= 1/\sqrt[3]{64}* 1/w^{14/3} *x^{10/3} * 1/y^{2} * z^{6}

= 1/4* 1/w^{14/3} *x^{10/3} * 1/y^{2} * z^{6}

=answer A

5 0
3 years ago
Brainliest + Points<br><br> Help and explain? So I could understand it?
tatiyna

Answer: A

golden ratio approximately equals:

(1+sqrt(5))/2=1.618

5/3=1.667

7/5=1.4

10/8=5/4=1.25

17/11=1.545

Change everything to decimal form and see what is closest.

So we can see that the photograph size of 5x3 is the best choice as it is the closest in size to the golden ratio.

Any questions at all please feel free to ask! Thank you so much!

5 0
4 years ago
Prove the identity. (tanx+1)^2=(1+2sinxcosx)/(cos^2x)
SOVA2 [1]
(\tan x+1)^2=\tan^2x+2\tan x+1
=\sec^2x+2\tan x
=\dfrac1{\cos^2x}+2\dfrac{\sin x}{\cos x}
=\dfrac1{\cos^2x}+\dfrac{2\sin x\cos x}{\cos^2x}
=\dfrac{1+2\sin x\cos x}{\cos^2x}
4 0
4 years ago
If(x) = x + 2 and h(x) = x-1, what is f • h](-3)?
deff fn [24]

Answer/Step-by-step explanation:

Composition functions are functions that combine to make a new function. We use the notation ◦ to denote a composition.

f ◦ g is the composition function that has f composed with g. Be aware though, f ◦ g is not

the same as g ◦ f. (This means that composition is not commutative).

f ◦ g ◦ h is the composition that composes f with g with h.

Since when we combine functions in composition to make a new function, sometimes we

define a function to be the composition of two smaller function. For instance,

h = f ◦ g (1)

h is the function that is made from f composed with g.

For regular functions such as, say:

f(x) = 3x

2 + 2x + 1 (2)

What do we end up doing with this function? All we do is plug in various values of x into

the function because that’s what the function accepts as inputs. So we would have different

outputs for each input:

f(−2) = 3(−2)2 + 2(−2) + 1 = 12 − 4 + 1 = 9 (3)

f(0) = 3(0)2 + 2(0) + 1 = 1 (4)

f(2) = 3(2)2 + 2(2) + 1 = 12 + 4 + 1 = 17 (5)

When composing functions we do the same thing but instead of plugging in numbers we are

plugging in whole functions. For example let’s look at the following problems below:

Examples

• Find (f ◦ g)(x) for f and g below.

f(x) = 3x + 4 (6)

g(x) = x

2 +

1

x

(7)

When composing functions we always read from right to left. So, first, we will plug x

into g (which is already done) and then g into f. What this means, is that wherever we

see an x in f we will plug in g. That is, g acts as our new variable and we have f(g(x)).

g(x) = x

2 +

1

x

(8)

f(x) = 3x + 4 (9)

f( ) = 3( ) + 4 (10)

f(g(x)) = 3(g(x)) + 4 (11)

f(x

2 +

1

x

) = 3(x

2 +

1

x

) + 4 (12)

f(x

2 +

1

x

) = 3x

2 +

3

x

+ 4 (13)

Thus, (f ◦ g)(x) = f(g(x)) = 3x

2 +

3

x + 4.

Let’s try one more composition but this time with 3 functions. It’ll be exactly the same but

with one extra step.

• Find (f ◦ g ◦ h)(x) given f, g, and h below.

f(x) = 2x (14)

g(x) = x

2 + 2x (15)

h(x) = 2x (16)

(17)

We wish to find f(g(h(x))). We will first find g(h(x)).

h(x) = 2x (18)

g( ) = ( )2 + 2( ) (19)

g(h(x)) = (h(x))2 + 2(h(x)) (20)

g(2x) = (2x)

2 + 2(2x) (21)

g(2x) = 4x

2 + 4x (22)

Thus g(h(x)) = 4x

2 + 4x. We now wish to find f(g(h(x))).

g(h(x)) = 4x

2 + 4x (23)

f( ) = 2( ) (24)

f(g(h(x))) = 2(g(h(x))) (25)

f(4x

2 + 4x) = 2(4x

2 + 4x) (26)

f(4x

2 + 4x) = 8x

2 + 8x (27)

(28)

Thus (f ◦ g ◦ h)(x) = f(g(h(x))) = 8x

2 + 8x.

4 0
3 years ago
How long dose it take to travel 5km at an average speed of 8 m/s? Give your answers in minutes and seconds
eduard

Answer:

625 seconds and 10 minutes

Step-by-step explanation:

distancs=S=5km=5000m

average speed=v=8m/s

time taken=t=?

as we know that

average speed=\frac{distance covered}{time taken}

average speed×time taken=distance covered

here we have to find the time taken

time taken=\frac{distance covered}{average speed}

time taken=\frac{5000m}{8m/s}

time taken=625seconds

now we convert seconds into minutes

\frac{625}{60}

10 minutes

4 0
4 years ago
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