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Otrada [13]
3 years ago
6

Which graphs represent functions?? please help me

Mathematics
1 answer:
muminat3 years ago
4 0

Answer:

graph D

Step-by-step explanation:

If you want to figure out if a graph is a function, try the vertical line test

The vertical line test is when you are able to draw a vertical line on any point of the graph, and the line you have drawn will only pass through the graph once. if it passes the graph more than one time, it is not a function

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What is the value of this expression?
saw5 [17]

Answer:

Hey

Step-by-step explanation:

Answer is b. 42

2(17+6)−4

8 0
2 years ago
Read 2 more answers
Please help! Write the intervals of the values shown on the graph below
Veseljchak [2.6K]
The answer is
-1 ≤ x < 3
We just learned this is in my algebra 2 AP class
5 0
2 years ago
Assortative mating is a nonrandom mating pattern where individuals with similar genotypes and/or phenotypes mate with one anothe
scZoUnD [109]

Answer:

a) P(male=blue or female=blue) = 0.71

b) P(female=blue | male=blue) = 0.68

c) P(female=blue | male=brown) = 0.35

d) P(female=blue | male=green) = 0.31

e) We can conclude that the eye colors of male respondents and their partners are not independent.

Step-by-step explanation:

We are given following information about eye colors of 204 Scandinavian men and their female partners.

              Blue    Brown     Green    Total

Blue        78         23            13          114

Brown     19         23            12          54

Green     11           9             16          36

Total      108       55            41          204

a) What is the probability that a randomly chosen male respondent or his partner has blue eyes?

Using the addition rule of probability,

∵ P(A or B) = P(A) + P(B) - P(A and B)

For the given case,

P(male=blue or female=blue) = P(male=blue) + P(female=blue) - P(male=blue and female=blue)

P(male=blue or female=blue) = 114/204 + 108/204 − 78/204

P(male=blue or female=blue) = 0.71

b) What is the probability that a randomly chosen male respondent with blue eyes has a partner with blue eyes?

As per the rule of conditional probability,

P(female=blue | male=blue) = 78/114

P(female=blue | male=blue) = 0.68

c) What is the probability that a randomly chosen male respondent with brown eyes has a partner with blue eyes?

As per the rule of conditional probability,

P(female=blue | male=brown) = 19/54

P(female=blue | male=brown) = 0.35

d) What is the probability of a randomly chosen male respondent with green eyes having a partner with blue eyes?

As per the rule of conditional probability,

P(female=blue | male=green) = 11/36

P(female=blue | male=green) = 0.31

e) Does it appear that the eye colors of male respondents and their partners are independent? Explain

If the following relation holds true then we can conclude that the eye colors of male respondents and their partners are independent.

∵ P(B | A) = P(B)

P(female=blue | male=brown) = P(female=blue)

or alternatively, you can also test

P(female=blue | male=green) = P(female=blue)

P(female=blue | male=blue) = P(female=blue)

But

P(female=blue | male=brown) ≠ P(female=blue)

19/54 ≠ 108/204

0.35 ≠ 0.53

Therefore, we can conclude that the eye colors of male respondents and their partners are not independent.

7 0
3 years ago
In August 2003, 56% of employed adults in the United States reported that basic mathematical skills were critical or very import
Serga [27]

Answer:

Yes

Step-by-step explanation:

First, suppose that nothing has changed, and possibility p is still 0.56. It's our null hypothesis. Now, we've got Bernoulli distribution, but 30 is big enough to consider Gaussian distribution instead.

It has mean μ= np =  30×0.56=16.8

standard deviation s = √npq

sqrt(30×0.56×(1-0.56)) = 2.71

So 21 is (21-16.8)/2.71 = 1.5494 standard deviations above the mean. So the level increased with a ˜ 0.005 level of significance, and there is sufficient evidence.

7 0
3 years ago
Find the perimeter of a rectangle with a length of 12 feet and a width of 6 feet.
jeka57 [31]
Perimeter= 2 ( length + width)
2×(12+6)
2×18
=36
3 0
3 years ago
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