22.8 grams of element will be remaining after 7 minutes
Further explanation:
Given
The element reduces (1-22%) in one minute.
The process will be repeated 7 times for 7 minutes
If we have to calculate the amount of element after 7 minutes
then the total reduction will be: (1-22%)^7
22.8 grams of element will be remaining after 7 minutes
Keywords: Decay, Percentage
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The perimeter of a parallelgram is the sum of the lengths of its four sides.
Parallelogram ABCD has sides AB, BC, CD, and AB.
Sides AB and CD are parallel and of equal length = 19 units.
Sides BC and CD are parallel and of equal length. Assuming thi is the length of 5 units given in the statement, the perimeter of the parallelogram ABCD is: 19 units + 19 units + 5 units + 5 units = 48 units.
Please, inform if the length of 5 units corresponds to other distance, but even in that case, with this explanation you should be able to calculate the perimeter of this and other parallelograms.
Answer: 48 untis.
Hey i would answer but you didn’t provide enough context! make sure to upload images with your question hun.
Answer:
Positive and negative intervals on a graph
Step-by-step explanation:
The positive regions of a function are those intervals where the function is above the x-axis. It is where the y-values are positive (not zero). The negative regions of a function are those intervals where the function is below the x-axis. It is where the y-values are negative (not zero). hope this helps you :)
Answer:
(-4, 0) U (1, ∞)
Step-by-step explanation:
Set each factor EQUAL to zero to find the zeroes (since it is not actually equal to zero, you will use an open circle when graphing and an open bracket when writing in interval notation).
x = 0 x-1 = 0 x + 4 = 0
x = 1 x = -4
Next, choose a value to the far left, between each of the zeroes, and to the far right to evaluate if it makes a true statement when input into the given inequality.
far left (I choose -5): -5(-5 - 1)(-5 + 4) > 0 → (-)(-)(-) > 0 → negative > 0 FALSE
- 4 to 0 (I choose -2): -2(-2 - 1)(-2 + 4) > 0 → (-)(-)(+) > 0 → positive > 0 TRUE
0 to 1 (I choose 0.5): .5(.5 - 1)(.5 + 4) > 0 → (+)(-)(+) > 0 → negative > 0 FALSE
far right (I choose 2): 2(2 - 1)(2 + 4) > 0 → (+)(+)(+) > 0 → positive > 0 TRUE
