Answer:
2kg
Step-by-step explanation:
Let the sum of the other 2 bricks be R. Given that the heaviest brick weighs 2/3 times as much as the other 2 bricks in total, then the weight of the heaviest brick H in terms of the weight of the other 2 will be
H = 2/3 * R
= 2R/3
Given that the 3 bricks weigh 5kg in total then,
2R/3 + R = 5
Multiply through the equation by 3
2R + 3R = 15
5R = 15
Divide both sides by 5
R = 15/5
= 3
The weight of the heaviest brick is 2R/3. Since R = 3, the heaviest block weighs
= 2 * 3/3
= 2kg
The answer is (2) 9x2-19x+5.Because you need to first put them together linking by minus sign
Answer:
-x-2; x
2
Step-by-step explanation:
-->
-->
-(x+2); x CAN'T equal 2, because the denominator of the original fraction would be 0, which would make the term undefined.
I would answer the problem but first upload the diagram