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3 years ago

What is the vertex of the parabola? y+4=12(x−7)2

2 answers:

5 0

The answer to this question is (7,-4).
The parabola y+4=12(x−7)^2 can be moved so that the y term is isolated like so
y = 12(x-7)^2 - 4
A parabola of the form y = a(x-h)^2 + k has its vertex at (h,k). So it follows that we take h = 7 and k = - 4.
The answer to this question is (7,-4).

Alborosie3 years ago

3 0

Vertex is (7,-4) for answer.

Hope this helps. :)

You might be interested in

Write the sum of 5x2 + 2x - 10 and 2x2 + 6 as a polynomial in standard form.

vaieri [72.5K]

Answer:

7x^2+2x-4

Step-by-step explanation:

a standard form is ax+by=c

5x^2 add 2x^2=7x^2 then -2x but when you have a -10 +6 you get -4 giving you the answer of 7x^2 +2x -4

7 0

3 years ago

Read 2 more answers

What is the solution to 2x-8 <12

Nookie1986 [14]

Step-by-step explanation:

2x-8<12

+8<+8

2x<20

$\frac{2x}{2} \frac{20}{2}$

x<10

4 0

3 years ago

Please help me with this! I will mark you as brainliest!

erastovalidia [21]

Step-by-step explanation:

$\frac{ {5}^{3} }{ {5}^{7} }$

$\frac{1}{ {5}^{7 - 3} }$

$\frac{1}{ {5}^{4} }$

${5}^{ - 4}$

Hope it will help :)

4 0

4 years ago

Find the perimeter of the triangle with vertices A(negative 2,2,3), B(4,negative 4,3), and C(7,6,4).

gayaneshka [121]

Answer:

$P\approx 28.872\,\text{units}$

Step-by-step explanation:

We are given coordinates of each of the vertices of the triangle ABC, hence we can use the distance formula to find the lengths of each of the side.

the distance formula is generally written as:

$r = \sqrt{(x_1-x_2)^2+(y_1-y_2)^2+(z_1-z_2)^2}$

for the side AB: A(-2,2,3) and B(4,-4,3)

$AB = \sqrt{(-2-4)^2+(2-(-4))^2+(3-3)^2}$

$AB = \sqrt{(-6)^2+(6)^2+(3-3)^2}$

$AB = \sqrt{72}$

for the side BC: B(4,-4,3) and C(7,6,4)

$BC = \sqrt{(4-7)^2+((-4)-6)^2+(3-4)^2}$

$BC = \sqrt{110}$

for the side CA: C(7,6,4) and A(-2,2,3)

$CA = \sqrt{(7-(-2))^2+(6-2)^2+(4-3)^2}$

$CA = \sqrt{98}$

Now we all the sidelengths:

to find the perimeter we need to just sum the three side lengths:

$P = AB + BC + CA$

$P = \sqrt{72} + \sqrt{110} + \sqrt{98}$

$P\approx 28.872\,\text{units}$

this is the perimeter of triangle ABC

6 0

3 years ago

Use the distributive property to remove the parenthesis (v+12)10

serg [7]

The distributive property means to distribute the number being multiplied by the numbers in the parentheses.
In this case, (v+12) is being multiplied by 10.
To solve this, you simply have to multiply 10 by each term inside the parentheses.
That means it would be (v•10)+(12•10).
(v•10) is equal to 10v, since v is the variable and we don't know its value.
(12•10) is equal to 120.
So by using the distributive property we can find that (v+12)10 = 10v+120.

6 0

3 years ago