Answer:
this doesn't have anymore info?
its incomplete
Step-by-step explanation:
Answer:
z (min) = 360 x₁ = x₃ = 0 x₂ = 3
Step-by-step explanation:
Protein Carbohydrates Iron calories
Food 1 (x₁) 10 1 4 80
Food 2 (x₂) 15 2 8 120
Food 3 (x₃) 20 1 11 100
Requirements 40 6 12
From the table we get
Objective Function z :
z = 80*x₁ + 120*x₂ + 100*x₃ to minimize
Subjet to:
Constraint 1. at least 40 U of protein
10*x₁ + 15*x₂ + 20*x₃ ≥ 40
Constraint 2. at least 6 U of carbohydrates
1*x₁ + 2*x₂ + 1*x₃ ≥ 6
Constraint 3. at least 12 U of Iron
4*x₁ + 8*x₂ + 11*x₃ ≥ 12
General constraints:
x₁ ≥ 0 x₂ ≥ 0 x₃ ≥ 0 all integers
With the help of an on-line solver after 6 iterations the optimal solution is:
z (min) = 360 x₁ = x₃ = 0 x₂ = 3
Answer:
10,13,14,20,30.............
Answer:
The "total loan cost" formula is what you'll need (and it is attached).
Interest =1.25 / 1,200 = 0.0010416667
and "n" is number of months (6 years = 72 months)
Total Loan Cost = (r*p*n) / 1 -((1 + r)^-n)
Total Loan Cost = (0.0010416667 * 12,000 * 72) / 1 -((1.0010416667)^-72)
Total Loan Cost = 900 / 1 -0.9277797019
Total Loan Cost = 900 / 0.0722202981
Total Loan Cost = 12,461.87
Step-by-step explanation:
Answer:
I am too!
Step-by-step explanation:
