Ask question

Ask question

All categories

lisabon 2012 [21]

3 years ago

14

PLEASE PLEASE HELP ME 30 POINTS! x + 20 ≤ -10

2 answers:

Archy [21]3 years ago

8 0

Answer:

x is less than -30

Artemon [7]3 years ago

7 0

X + 20 <= -10

Subtract 20 from both sides:

X <= -30

You might be interested in

Activity 1.1 Simplify Me Simplify by removing perfect nth powers: 1. √20 2. √300 3. √128 3 4. √ 5 3 5. √50 3

LekaFEV [45]

Answer:

$(a)\ \sqrt{20}=2\sqrt{5}$

$(b)\ \sqrt{300} = 10 \sqrt{3}$

$(c)\ \sqrt{128} = 8 \sqrt{2}$

Step-by-step explanation:

Required

Simplify

$(a)\ \sqrt{20}$

Express 20 as 4 * 5

$\sqrt{20}=\sqrt{4 * 5}$

Split

$\sqrt{20}=\sqrt{4} * \sqrt{5}$

This gives:

$\sqrt{20}=2 * \sqrt{5}$

$\sqrt{20}=2\sqrt{5}$

$(b)\ \sqrt{300$

Express as 100 * 3

$\sqrt{300} = \sqrt{100} * \sqrt{3}$

This gives:

$\sqrt{300} = 10 * \sqrt{3}$

$\sqrt{300} = 10 \sqrt{3}$

$(c)\ \sqrt{128}$

Express as 64 * 2

$\sqrt{128} = \sqrt{64*2}$

Split

$\sqrt{128} = \sqrt{64} * \sqrt{2}$

$\sqrt{128} = 8 * \sqrt{2}$

$\sqrt{128} = 8 \sqrt{2}$

<em></em>

<em>Questions 4 and 5 are not clear</em>

<em>Follow the steps in 1 - 3 to solve 4 and 5</em>

7 0

2 years ago

Please i really need it rn pls

Step2247 [10]

The 3rd option is correct

7 0

2 years ago

Read 2 more answers

Determine the domain of the function.

pav-90 [236]

$Domain \ of \ \frac{\sqrt{x + 3}}{(x + 8)(x - 2)}=(-3\leq x < 2) \cup (2 < x < \infty)$

i.e. x ≥ –3, x ≠ 2

4 0

2 years ago

Round 10,031.464 to the nearest hundred.

insens350 [35]

Answer:

10,031.46

Rounded to the nearest 0.01 or

the Hundredths Place.

Step-by-step explanation:

7 0

3 years ago

55x5<img src="https://tex.z-dn.net/?f=55x5%3D%5C%5C" id="TexFormula1" title="55x5=\\" alt="55x5=\\" align="absmiddle" class="lat

mash [69]

Answer:

55 times 5 is 275

Step-by-step explanation:

what's the other stuff

5 0

3 years ago