N represents the quantum number. for n = 3, there are 3 possible sublevels that are 3s, 3p and 3d.
There are four sublevels that are s, p, d and f. In s subshell or sublevel there is 1 orbital, in p sublevel there is 3 orbitals, in d sublevel there is 5 orbitals and in d sublevel there is 7 orbitals.
And there are 2, 6, 10 and 14 maximum number of electrons in s, p, d and f sublevels respectively.
Answer:
0.80589
Step-by-step explanation:
So all of the numbers of correct answers less than 4 are 0,1,2,3
We need to calculate the probability for each separately and then add them together.
To find the probability we have to first find the combination. We know that there’s n=8 trials and that p=0.3. So 1-0.3 gives us 0.7.
The combination formula is: ! / (!(−)!)
So the n would always =8, and the r would be 0,1,2,3. So you would have to calculate it for 0,1,2,3 Separately. This can be done by hand or you can use a simple combinations calculator online.
For 0;
The combination is 1,
1 x 0.3^0 x 0.7^8-0 =
0.057648
For 1;
The combination is 8,
8 x 0.3^1 x 0.7^8-1 =
0.19765
For 2;
The combination is 28
28 x 0.3^2 x 0.7^8-2 =
0.296475
For 3;
The combination is 56
56 x 0.3^3 x 0.7^8-3 =
0.254122
All that’s left is to add these four numbers;
0.057647 + 0.19765 + 0.296475 + 0.254122 = 0.80589
Answer:
Let's define the variables:
A = price of one adult ticket.
S = price of one student ticket.
We know that:
"On the first day of ticket sales the school sold 1 adult ticket and 6 student tickets for a total of $69."
1*A + 6*S = $69
"The school took in $150 on the second day by selling 7 adult tickets and student tickets"
7*A + 7*S = $150
Then we have a system of equations:
A + 6*S = $69
7*A + 7*S = $150.
To solve this, we should start by isolating one variable in one of the equations, let's isolate A in the first equation:
A = $69 - 6*S
Now let's replace this in the other equation:
7*($69 - 6*S) + 7*S = $150
Now we can solve this for S.
$483 - 42*S + 7*S = $150
$483 - 35*S = $150
$483 - $150 = 35*S
$333 = 35*S
$333/35 = S
$9.51 = S
That we could round to $9.50
That is the price of one student ticket.
Answer:
The answer is D.
Step-by-step explanation:
40.5 multiplied by 21 is 850.5
