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3 years ago

There are 135 cal in a 1/4 cup serving of trail mix how many calories are in 2 cups of trail mix?

2 answers:

8 0

Answer: 1,080

Explanation: if you have 1/4 cup that has 135 calories to get you to two cups you have to multiply by eight because there is 4 1/4 cups in 1 cups and you double that and you have to do the same with the calories so 135 • 8=1,080

damaskus [11]3 years ago

5 0

Answer:

1080 cal will be in 2 cups of trail mix

Step-by-step explanation:

If 135 cal = 1/4 cups

? cal = 2 cups

This is obtained by representing the unknown value of calories with a variable say Z, and the cross multiply to get a general equation. i.e.

135cal = 1/4 cups

Z cal = 2 cups

So therefore,

Z cal X 1/4 cups = 135cal X 2 cups

To get the value of Z, divide both sides by 1/4 cups;

Z cal = 135 cal X 2 X 4 ( cups cancel out)

Z cal = 1080 cal

Z = 1080; Therefore it takes 1080cal to be in 2 cup trail mix.

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The steps for determining the center and radius of a circle using the completing the square method are shown below: Step 1 [orig

Alika [10]

We are given original equation: $x^2 -10x + y^2 + 12y = 20$

We need to find the enter and radius of a circle using the completing the square method.

The steps are as following :

Step 1 [original equation]: x^2 − 10x + y^2 + 12y = 20 .

Step 2 [group like terms]: (x^2 − 10x) + (y^2 + 12y) = 20

Step 3 [complete the quadratics]: (x^2 − 10x + 25) + (y^2 + 12y + 36) = 20 + (25 + 36).

Step 4 [simplify the equation]: (x^2 − 10x + 25) + (y^2 + 12y + 36) = 64.

Step 5 [factor each quadratic]: (x − 5)^2 + (y + 6)^2 = 8^2

Step 6 [identify the center and radius]: Center = (5, −6) Radius = 8.

<h3>Step 6 is incorrect.</h3><h3>The center should be (5,-6).</h3><h3> Replace − 5 with + 5 and replace + 6 with − 6.</h3>

7 0

3 years ago

I am Lyosha [343]

You have the right idea that things need to get multiplied.

What should be done is that the entire fraction needs to get multipled by the lowest common denominator of both denominators.

Let's look at the complex numerator. Its denominators are 5 and x + 6. Nothing is common with these, so both pieces are needed.

The complex denominator has x - 3 as its denominator. With nothing in common between it and the complex numerator, that piece is needed.

So we multiply the entire complex fraction by (5)(x + 6)(x -3).

Numerator: $(\frac{1}{5} -\frac{5}{x + 6})(5)(x +6)(x-3) =\frac{1}{5}(5)(x +6)(x-3) - \frac{5}{x + 6}(5)(x +6)(x-3)$

= (x+6)(x-3) - (5)(5)(x-3)

= (x+6)(x-3) - 25(x-3)

= (x-3)(x + 6 - 25) <--- by group factoring the common x - 3

= (x -3)(x - 19)

Denominator:

$\frac{25}{x - 3} * (5)(x + 6)(x - 3) = (25)(5)(x + 6) = 125(x + 6)$

Now we put the pieces together.

Our fraction simplies to (x - 3) (x - 19) / 125 (x + 6)

5 0

3 years ago

What's the answer......

Licemer1 [7]

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8 0

3 years ago

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kykrilka [37]

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2 years ago

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A box contains cards bearing numbers from 6 to 70. If one card is drawn at random from the box, find the probability that it bea

777dan777 [17]

Answer:

a) 4/65 b) 13/65 c) 12/65 d) 19/65

Step-by-step explanation:

Probability is the likelihood or chance that an event might occur.

Probability = expected outcome of event/Total outcome of event

If a box contains cards bearing numbers from 6 to 70, the total outcome will be the total number present from 6 to 70 which is 65

a) The amount of one digit number we have are 4 i.e {6,7,8,9}. This will be our expected outcome in this case.

The probability that the number drawn bears a one digit number will be 4/65

b) For numbers divisible by 5, the numbers that are divisible by 5 from the number drawn are {10, 15, 20, 25, 30, 35, 40, 45, 50, 55, 60, 65, 70}

The total expected outcome in this case = 13

The probability that the number drawn is divisible by 5 = 13/65

c) For odd numbers less than 30, they are {7,9,11,13,15,17,19,21,23,25,27,29}

The total expected outcome in this case = 12

The probability that the number drawn are odd numbers less than 30 = 12/65

d) For composite number between 50 and 70, this are numbers that are within this range and they includes {51,52,53,54,55,56,57,58,59,60,61,62,63,64,65,66,67,68,69}

The total expected outcome in this case = 19

The probability that the number drawn are composite numbers between 50 and 70= 19/65

8 0

3 years ago