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alex41 [277]
4 years ago
11

Christina is making a salad for a dinner party with 1.78 pounds of lettuce and 4.36 pounds of tomatoes.

Mathematics
1 answer:
gizmo_the_mogwai [7]4 years ago
6 0

Answer:

A) 2.58 pounds

Step-by-step explanation:

To solve you would have to subtract the pounds of tomatoes from the pounds of lettuce. The equation would look like this,

4.36 - 1.78 = 2.58

Hope that helps and have a great day!

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The Fruity Juice Company has decided to produce and sell their juice Hairy Mango T M. They are about to begin production, but ne
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Answer:

a) Price demand function = D = -40P + 8000

b) Revenue function = R = -40P² + 8000P

c) Price P = 100 cents and Revenue R = 4×10⁵ cents

Step-by-step explanation:

We are given quantity and price of Hairy Mango T M juice

Let P represents price in cents and D represents demand

D₁ = 5400

D₂ = 6000

P₁ = 65

P₂ = 50

(a) Find a formula for the price/demand function based on the data.

The demand and price relationship can be modeled as a linear relationship,

D = aP + b

Substitute the given data points into above equation

5400 = 65a + b     eq. 1

6000 = 50a + b     eq. 2

Solving eq. 1 and eq, 2 simultaneously,

b = 6000 - 50a

5400 = 65a + (6000 - 50a)

5400 - 6000 = 65a - 50a

-600 = 15a

a = -600/15

a = -40

b = 6000 - 50a

b = 6000 - 50(-40)

b = 6000 + 2000

b = 8000

So the price demand function becomes,

D = aP + b

D = -40P + 8000

(b) Find a formula for the revenue function.

The revenue function is given by

R = D*P

R = (-40P + 8000)*P

R = -40P² + 8000P

(c) Find the price they should charge to generate the maximum revenue, then calculate the maximum revenue. (Round to the nearest cent)

Maximum revenue is obtained when

dR/dp = 0

dR/dp = -40P² + 8000P

dR/dp = -80P + 8000

0 = -80P + 8000

80P = 8000

P = 8000/80

P = 100 cents

The maximum revenue is

R = -40(100)² + 8000(100)

R = -400000 + 800000

R = 400000 cents

R = 4×10⁵ cents

Therefore, the maximum revenue is 4×10⁵ cents when the price is set to 100 cents.

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