Answer:
59.25 < hb ≤ 86.25 (also = 59.3 < 1dp ≤ 86.2 to 1dp)
Step-by-step explanation:
60- 0.75 = human height therefore 59.25 < h ≤ ? then to find greatest height we subtract again 87 - 0.75 = 86.25 and fill in 59.25 < h ≤ ? = 59.25 < h ≤ 86.25 and should we show inhes to 1 dp we keep lowest rounded up 59.3 < 1dp ≤ 86.2 as lowest bound is 59.15 < lb ≤ 86.15 = 59.25 < hb ≤ 86.25
The simplified answer is 1/12.
Answer:
(-4,-2)
Step-by-step explanation:
Point f is on x -4, which is in the first slot and y -2 which is your second slot
The X-intercepts: (1,0),(-7,0)
Axis of symmetry: x= - 3
The vertex: (-3, -8)
The Y-intercept: (0, -7/2)
Concave up or down: concave up
Sketch: a poorly drawn picture on the bottom.
I hope that helps.
Answer:
The area of one trapezoidal face of the figure is 2 square inches
Step-by-step explanation:
<u><em>The complete question is</em></u>
The point of a square pyramid is cut off, making each lateral face of the pyramid a trapezoid with the dimensions shown. What is the area of one trapezoidal face of the figure?
we know that
The area of a trapezoid is given by the formula

where
b_1 and b-2 are the parallel sides
h is the height of the trapezoid (perpendicular distance between the parallel sides)
we have

substitute the given values in the formula

