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Jlenok [28]
3 years ago
5

Write an equation of the line given.​

Mathematics
1 answer:
frozen [14]3 years ago
6 0

Answer:

y = -3/4x + 1

Step-by-step explanation:

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-(10)=1000<br><br>{True or False}<br><br>free 50​
velikii [3]

Answer:

false

Step-by-step explanation:

8 0
3 years ago
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HELP PLEASE. Solve. 6(x+20)=168
KiRa [710]

Answer:

x=8

Step-by-step explanation:

6(x+20)=168

Divide each side by 6

6/6(x+20)=168/6

x+20 =28

Subtract 20 from each side

x+20-20 = 28-20

x =8

4 0
3 years ago
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What is the explicit rule for the geometric sequence?
makvit [3.9K]
The answer is C. The formula for a geometric sequence is an = a1*r^n-1. If we plug in our numbers, we get an = 400*1/2^n-1. That is the same as C.
6 0
3 years ago
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11) A marketing research company is estimating the average total compensation of CEOs in the service industry. Data were randoml
Illusion [34]

Answer:

The confidence interval would be more narrow if the confidence level were changed to 90%

Step-by-step explanation:

For a small sample size of n = 18 a pivotal quantity that we can use to form a confidence interval for \mu is given by T=\frac{\bar{X}-\mu}{S/\sqrt{n}} that has a t distribution with (n-1) degrees of freedom. We find a 100(1-\alpha)% confidence inverval using P(-t_{\alpha/2}\leq T \leq t_{\alpha/2}) = 1-\alpha, where t_{\alpha/2} is the t-value such that there is an area equal to \alpha/2 above this t-value and below the curve of the density of the t distribution with n-1 df. We find a 95% confidence interval with P(-t_{0.025}\leq T\leq t_{0.025}) = 0.95 and we find a 90% confidence interval with P(-t_{0.05}\leq T\leq t_{0.05}) = 0.90. Because of -t_{0.025} < -t_{0.05} and t_{0.05} < t_{0.025}, the confidence interval would be more narrow if the confidence level were changed to 90%.

5 0
3 years ago
Evaluate -7x + y5x<br> When x = -3, y = -9
Semmy [17]

Answer:

156

Step-by-step explanation:

-7(-3)+(-9)(5)(-3)

21+135

156

8 0
3 years ago
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