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3 years ago

3/4a - q = k (solve for a) please show work, thanks!

Mathematics

2 answers:

Iteru [2.4K]3 years ago

8 0

Answer:

a = 4/3k + 4/3q

Step-by-step explanation:

3/4a - q = k

+q +q

3/4a = k + q

*4/3 *4/3

a = 4/3k + 4/3q

juin [17]3 years ago

8 0

Step-by-step explanation:

3/4a -q =k //// plus q

3/4a =k -q //// divided by 3/4

a =(k-q)/(3/4)

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$\large \boxed{\sf \ \ x=\pm8 \ \ or \ \ x=\pm2 \ \ }$

Step-by-step explanation:

Hello, please consider the following.

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And from the first equation we can write y as a function of x as below.

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$\dfrac{x}{\frac{16}{x}}+\dfrac{\frac{16}{x}}{x}=\dfrac{17}{4}\\\\ \dfrac{x^2}{16}+\dfrac{16}{x^2}=\dfrac{17}{4}\\\\\text{*** We multiply by }16x^2 \text{ both sides ***}\\\\x^4+16*16=\dfrac{17*16}{4}x^2\\\\x^4-68x^2+3600=0\\\\\text{*** The product of the zeroes is 3600 = 64*4 and the sum is 64+4=68 ***}\\\\\text{*** So we can factorise *** }\\\\x^4-64x^2-4x^2+3600=x^2(x^2-64)-4(x^2-64)=(x^2-64)(x^2-4)=0\\\\x^2=64=8^2 \ \ or \ \ x^2=4\\\\x=\pm8 \ \ or \ \ x=\pm2\\$

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

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