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romanna [79]
4 years ago
5

You have 18 tbsp of onion powder

Mathematics
1 answer:
aniked [119]4 years ago
6 0

Answer: 9

2 tbsp = 1 serving of spice rub.

18 tbsp = 9 servings of spice rub because 18 ÷ 2 = 9.

Hope it helped!

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A recipe for one batch of cookies uses 5 cups of flour and 2 teaspoons of vanilla. If you use 6 teaspoons of vanilla, how many c
SCORPION-xisa [38]

Answer:

15 cups of flour

Step-by-step explanation:

if the vanilla is going from 2 - 6 then it is being multipled by 3. Therfore you should multiply the flour (5) by 3, which makes the total flour to be 15 cups.

3 0
3 years ago
Read 2 more answers
Please help me with this graph!
trasher [3.6K]

Answer:

y=4/3x-1

Step-by-step explanation:

5 0
3 years ago
Find the x and y intercepts of the graph of the equation y=x^2-5
mr_godi [17]

Answer:

x intercepts  -sqrt(5), + sqrt(5)

y intercept -5

Step-by-step explanation:

y = x^2 -5

to find the x intercept set y=0 and solve for x

0 = x^2-5

add 5 to each side

5 = x^2

take the square root of each side

+- sqrt(5) = sqrt(x^2)

x = +-sqrt(5)    there are 2 x intercepts since it is a quadratic


to find the y intercept set x=0 and solve for y

y = 0-5

y = -5

8 0
3 years ago
Ron’s class donated d dollars to a local charity. Danny’s class donated 21% more than Ron’s class. Which expression shows the am
Savatey [412]
DX1.21 because 1.21 means 21 percent more than d

6 0
4 years ago
A poll reported that 66% of adults were satisfied with the job the major airlines were doing. Suppose 20 adults are selected at
NARA [144]

Answer:

0.5640

Step-by-step explanation:

n = 12 (number of adults)

p = 0.65 (probability that an adult is satisfied with the job the major airlines were doing.

x = number of adults out of 11 who were satisfied.

a)

P( x = 5) = 11C5 (0.65)^5 (0.35)^6 = 0.0986

b)

P( x < 3) = P(x=0)+P(x=1)+P(x=2)

P( x =0) = 11C0 (0.65)^0 (0.35)^11 = 0.0000

P( x =1) = 11C1 (0.65)^1 (0.35)^10 = 0.0002

P( x =2) = 11C2 (0.65)^2 (0.35)^9 = 0.0018

Add: P( x < 3) = 0.0020

c)

P( x ≥ 8) = P(x=8)+P(x=9)+P(x=10)+P(x=11)

P( x =8) = 11C8 (0.65)^8 (0.35)^3 = 0.2254

P( x =9) = 11C9 (0.65)^9 (0.35)^2 = 0.1395

P( x =10) = 11C10 (0.65)^10 (0.35)^1 = 0.0518

P( x =11) = 11C11 (0.65)^11 (0.35)^0 = 0.0087

add:

P( x ≥ 8) = 0.4254

d)

P(x=4)+P(x=5)+P(x=6)+P(x=7)

P( x =4) = 11C4 (0.65)^4 (0.35)^7 = 0.0379

P( x =5) = 11C5 (0.65)^5 (0.35)^6 = 0.0985

P( x =6) = 11C6 (0.65)^6 (0.35)^5 = 0.1830

P( x =7) = 11C7 (0.65)^7 (0.35)^4 = 0.2428

Add: 0.5640

8 0
3 years ago
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