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3 years ago

Find m if the line y=mx−2 intersects y=x^2 in just one point. (WILL GIVE BRANLIEST)

Mathematics

2 answers:

SIZIF [17.4K]3 years ago

8 0

Answer:

anything over ten

Step-by-step explanation:

Try to get a line that is completely vertical.

10 will work, as well as many other numbers, unless i misunderstood the question

MrMuchimi3 years ago

5 0

Answer:

m = 2root2 or -2root2

Step-by-step explanation:

See the attached graph. We know that it can't be greater than 3, otherwise there are two solutions, and it can't be less than 2, otherwise there are no solutions. The only thing that works is either 2root2 or -2root2. (Root stands for square root.)

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Korey runs every 3rd day and swims every 4th day. If he runs and swims today, how many days will it be before Korey runs and swi

hichkok12 [17]

Answer: 12 days

Step-by-step explanation:

Based on the question, we have to list the multiples of 3 and 4. This will be:

3 = 3, 6, 9, 12, 15, 18, 21, 24, 27, 30

4 = 4, 8, 12, 16, 20, 24, 28, 32, 36, 40.

The lowest common multiple is 12.

It will take 12 days before Korey runs and swims again on the same day.

5 0

3 years ago

<img src="https://tex.z-dn.net/?f=2%28x%20-%208%29%20%2B%204x%20%3D%206%28x%20-%202%29%20-%204" id="TexFormula1" title="2(x - 8)

Flauer [41]

In this question, you're solving for x.

Solve for x:

2(x - 8) + 4x = 6(x - 2) - 4

Distribute the 2 to the variables inside the parenthesis.

2x - 16 + 4x = 6(x - 2) - 4

Distribute the 6 to the variables inside the parenthesis.

2x - 16 + 4x = 6x - 12 - 4

6x - 16 = 6x - 12 - 4

6x - 16 = 6x - 16

Subtract 6x from both sides

-16 = -16

Add 16 to both sides

0 = 0

Answer:

All real numbers and solutions

8 0

3 years ago

Read 2 more answers

Write the following using algebraic notation, using the letter x for any unknown numbers:

Mnenie [13.5K]

Answer:

$\dfrac{x+7}{5}$

Step-by-step explanation:

The given statement is "I think of a number, add seven then divide by five".

Let the unknown number be x.

Now, add 7 to the number = x+7

If we divided them by 5, $\dfrac{x+7}{5}$ .

So, the required algebraic notation is $\dfrac{x+7}{5}$ .

6 0

3 years ago

Find an equation of the tangent plane to the given parametric surface at the specified point.

Neko [114]

Answer:

Equation of tangent plane to given parametric equation is:

$\frac{\sqrt{3}}{2}x-\frac{1}{2}y+z=\frac{\pi}{3}$

Step-by-step explanation:

Given equation

$r(u, v)=u cos (v)\hat{i}+u sin (v)\hat{j}+v\hat{k}$ ---(1)

Normal vector tangent to plane is:

$\hat{n} = \hat{r_{u}} \times \hat{r_{v}}\\r_{u}=\frac{\partial r}{\partial u}\\r_{v}=\frac{\partial r}{\partial v}$

$\frac{\partial r}{\partial u} =cos(v)\hat{i}+sin(v)\hat{j}\\\frac{\partial r}{\partial v}=-usin(v)\hat{i}+u cos(v)\hat{j}+\hat{k}$

Normal vector tangent to plane is given by:

$r_{u} \times r_{v} =det\left[\begin{array}{ccc}\hat{i}&\hat{j}&\hat{k}\\cos(v)&sin(v)&0\\-usin(v)&ucos(v)&1\end{array}\right]$

Expanding with first row

$\hat{n} = \hat{i} \begin{vmatrix} sin(v)&0\\ucos(v) &1\end{vmatrix}- \hat{j} \begin{vmatrix} cos(v)&0\\-usin(v) &1\end{vmatrix}+\hat{k} \begin{vmatrix} cos(v)&sin(v)\\-usin(v) &ucos(v)\end{vmatrix}\\\hat{n}=sin(v)\hat{i}-cos(v)\hat{j}+u(cos^{2}v+sin^{2}v)\hat{k}\\\hat{n}=sin(v)\hat{i}-cos(v)\hat{j}+u\hat{k}\\$

at u=5, v =π/3

$=\frac{\sqrt{3} }{2}\hat{i}-\frac{1}{2}\hat{j}+\hat{k}$ ---(2)

at u=5, v =π/3 (1) becomes,

$r(5, \frac{\pi}{3})=5 cos (\frac{\pi}{3})\hat{i}+5sin (\frac{\pi}{3})\hat{j}+\frac{\pi}{3}\hat{k}$

$r(5, \frac{\pi}{3})=5(\frac{1}{2})\hat{i}+5 (\frac{\sqrt{3}}{2})\hat{j}+\frac{\pi}{3}\hat{k}$

$r(5, \frac{\pi}{3})=\frac{5}{2}\hat{i}+(\frac{5\sqrt{3}}{2})\hat{j}+\frac{\pi}{3}\hat{k}$

From above eq coordinates of r₀ can be found as:

$r_{o}=(\frac{5}{2},\frac{5\sqrt{3}}{2},\frac{\pi}{3})$

From (2) coordinates of normal vector can be found as

$n=(\frac{\sqrt{3} }{2},-\frac{1}{2},1)$

Equation of tangent line can be found as:

$(\hat{r}-\hat{r_{o}}).\hat{n}=0\\((x-\frac{5}{2})\hat{i}+(y-\frac{5\sqrt{3}}{2})\hat{j}+(z-\frac{\pi}{3})\hat{k})(\frac{\sqrt{3} }{2}\hat{i}-\frac{1}{2}\hat{j}+\hat{k})=0\\\frac{\sqrt{3}}{2}x-\frac{5\sqrt{3}}{4}-\frac{1}{2}y+\frac{5\sqrt{3}}{4}+z-\frac{\pi}{3}=0\\\frac{\sqrt{3}}{2}x-\frac{1}{2}y+z=\frac{\pi}{3}$

5 0

3 years ago

I sold 6 coats for 60$ each. my commission is 20%, how much did I make

disa [49]

My answer would be 160

6 0

3 years ago

Read 2 more answers