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katrin [286]
3 years ago
11

Which statement accurately describes how to perform a 90° counterclockwise rotation of point A (−1, −2) around the origin? Creat

e a circle with point A as its center and a radius of the origin and point A, then locate a point on the circle that is 90° clockwise from point A. Create a circle with point A as its center and a radius of the origin and point A, then locate a point on the circle that is 90° counterclockwise from point A. Create a circle with the origin as its center and a radius of the origin and point A, then locate a point on the circle that is 90° clockwise from point A. Create a circle with the origin as its center and a radius of the origin and point A, then locate a point on the circle that is 90° counterclockwise from point A. ​

Mathematics
2 answers:
Anastaziya [24]3 years ago
8 0

Answer:

last one

Step-by-step explanation:

You are swinging A(-1,-2) around the center which in this case is the origin. Keep in mind that points on a circle all have a equal distance from the origin.  We don't want the distance from the center to change.

We want the center of that circle to be the origin.

So the answer is the last one:

"Create a circle with the origin as its center and a radius of the origin and point A, then locate a point on the circle that is 90° counterclockwise from point A. ​"

SOVA2 [1]3 years ago
5 0

Answer:

Option D.

Step-by-step explanation:

We need to perform a 90° counterclockwise rotation of point A (−1, −2) around the origin.

In rotation, the point and its image are equidistant from the center of rotation.

We know that all the points on a circle are equidistant from the center.

Steps for 90° counterclockwise rotation of point A (−1, −2) around the origin are:

1. Create a circle with the origin as its center and a radius of the origin and point A.

2. Locate a point on the circle that is 90° counterclockwise from point A.

Therefore, the correct option is D.

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Answer:

The equation has infinitely many solutions for any value of P and Q such that P=Q.

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Px - 37 = Qx - 37

Px - Qx - 37 = -37

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