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3 years ago

hich function has a range of {y|y ≤ 5}? f(x) = (x – 4)2 + 5 f(x) = –(x – 4)2 + 5 f(x) = (x – 5)2 + 4 f(x) = –(x – 5)2 + 4

Mathematics

1 answer:

Brums [2.3K]3 years ago

6 0

Answer:

$f(x)=-(x-4)^2+5$

Step-by-step explanation:

The function $f(x)=-(x-4)^2+5$ has the vertex at $(4,5)$ .

Since $a=-1\:$ , the graph of the function is a maximum graph.

The highest y-value is the y-coordinate of the vertex which is 5.

Therefore the range is { $y|y\le 5$ }

Therefore the correct answer is B.

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Answer:

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Step-by-step explanation:

From Geometric Mean Theorem we know that,

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So, Above theorem apply in the diagram;

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