Question

hich function has a range of {y|y ≤ 5}? f(x) = (x – 4)2 + 5 f(x) = –(x – 4)2 + 5 f(x) = (x – 5)2 + 4 f(x) = –(x – 5)2 + 4

Answer 1

Answer:

$f(x)=-(x-4)^2+5$

Step-by-step explanation:

The function $f(x)=-(x-4)^2+5$ has  the vertex at $(4,5)$.

Since $a=-1\:$, the graph of the function is a maximum graph.

The highest y-value is the y-coordinate of the vertex which is 5.

Therefore the range is {$y|y\le 5$}

Therefore the correct answer is B.