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3 years ago

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Jim is making salsa recipe calls for 3 1/3 cups of tomato sauce for every 1/6 cups of the cilantro if Jim has one cup of cilantr

o how many cups of tomato sauce with he need

1 answer:

RoseWind [281]3 years ago

6 0

Since there are a total of 6 cups of cilantro just multiply 3 1/3 by 6.
Jim will need 20 cups of tomato sauce.

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Please help me i dont understand <br> x - 9x + 3 +8x -3

stiv31 [10]

Answer:

Step-by-step explanation:

Collect the like terms!

x-9x+8x+3-3

Now simplify,

-8x+8x+0

0+0

Answer = 0

4 0

3 years ago

Read 2 more answers

Answer the question in the picture

Schach [20]

The area of the semicircle is A = 1187.9 cm².

<h3>What is the area of a circle?</h3>

The area of a circle with a radius of r is A = πr².

Given that, the diameter of the semicircle is 55 cm.

The radius of the semicircle is,

r = 55/2

The area of a semicircle is given by,

A = (1/2)πr²

Substitute the values,

A = (1/2)π(55/2)²

A = 1187.9

Hence, the area of the semicircle is A = 1187.9 cm².

Learn more about the area of a circle:

brainly.com/question/22964077

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6 0

2 years ago

Please help me in really confused

Marina86 [1]

The chart on the side should help you out. The width of a doorway is approximately 1 meter and the height of a skyscraper is 1,000 meters. Divide the height of the skyscraper by the width of the doorway to get your answer. It would take 1,000 door widths to make up the height of a skyscraper, so the height of the skyscraper is 1,000 times the width of the doorway.

5 0

3 years ago

A vehicle factory manufactures cars. The unit cost C (the cost in dollars to make each car) depends on the number of cars made.

NeTakaya

Answer:

The minimum cost is $9,105

Step-by-step explanation:

<em>To find the minimum cost differentiate the equation of the cost and equate the answer by 0 to find the value of x which gives the minimum cost, then substitute the value of x in the equation of the cost to find it</em>

∵ C(x) = 0.5x² - 130x + 17,555

- Differentiate it with respect to x

∴ C'(x) = (0.5)(2)x - 130(1) + 0

∴ C'(x) = x - 130

Equate C' by 0 to find x

∵ x - 130 = 0

- Add 130 to both sides

∴ x = 130

∴ The minimum cost is at x = 130

Substitute the value of x in C(x) to find the minimum unit cost

∵ C(130) = 0.5(130)² - 130(130) + 17,555

∴ C(130) = 9,105

∵ C(130) is the minimum cost

∴ The minimum cost is $9,105

4 0

3 years ago

For each vector field f⃗ (x,y,z), compute the curl of f⃗ and, if possible, find a function f(x,y,z) so that f⃗ =∇f. if no such f

butalik [34]

$\vec f(x,y,z)=(2yze^{2xyz}+4z^2\cos(xz^2))\,\vec\imath+2xze^{2xyz}\,\vec\jmath+(2xye^{2xyz}+8xz\cos(xz^2))\,\vec k$

Let

$\vec f=f_1\,\vec\imath+f_2\,\vec\jmath+f_3\,\vec k$

The curl is

$\nabla\cdot\vec f=(\partial_x\,\vec\imath+\partial_y\,\vec\jmath+\partial_z\,\vec k)\times(f_1\,\vec\imath+f_2\,\vec\jmath+f_3\,\vec k)$

where $\partial_\xi$ denotes the partial derivative operator with respect to $\xi$ . Recall that

$\vec\imath\times\vec\jmath=\vec k$

$\vec\jmath\times\vec k=\vec i$

$\vec k\times\vec\imath=\vec\jmath$

and that for any two vectors $\vec a$ and $\vec b$ , $\vec a\times\vec b=-\vec b\times\vec a$ , and $\vec a\times\vec a=\vec0$ .

The cross product reduces to

$\nabla\times\vec f=(\partial_yf_3-\partial_zf_2)\,\vec\imath+(\partial_xf_3-\partial_zf_1)\,\vec\jmath+(\partial_xf_2-\partial_yf_1)\,\vec k$

When you compute the partial derivatives, you'll find that all the components reduce to 0 and

$\nabla\times\vec f=\vec0$

which means $\vec f$ is indeed conservative and we can find $f$ .

Integrate both sides of

$\dfrac{\partial f}{\partial y}=2xze^{2xyz}$

with respect to $y$ and

$\implies f(x,y,z)=e^{2xyz}+g(x,z)$

Differentiate both sides with respect to $x$ and

$\dfrac{\partial f}{\partial x}=\dfrac{\partial(e^{2xyz})}{\partial x}+\dfrac{\partial g}{\partial x}$

$2yze^{2xyz}+4z^2\cos(xz^2)=2yze^{2xyz}+\dfrac{\partial g}{\partial x}$

$4z^2\cos(xz^2)=\dfrac{\partial g}{\partial x}$

$\implies g(x,z)=4\sin(xz^2)+h(z)$

Now

$f(x,y,z)=e^{2xyz}+4\sin(xz^2)+h(z)$

and differentiating with respect to $z$ gives

$\dfrac{\partial f}{\partial z}=\dfrac{\partial(e^{2xyz}+4\sin(xz^2))}{\partial z}+\dfrac{\mathrm dh}{\mathrm dz}$

$2xye^{2xyz}+8xz\cos(xz^2)=2xye^{2xyz}+8xz\cos(xz^2)+\dfrac{\mathrm dh}{\mathrm dz}$

$\dfrac{\mathrm dh}{\mathrm dz}=0$

$\implies h(z)=C$

for some constant $C$ . So

$f(x,y,z)=e^{2xyz}+4\sin(xz^2)+C$

3 0

4 years ago