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Gnesinka [82]
3 years ago
9

What is the solution to y = 3x + 2 for the replacement set x = {1.1}?

Mathematics
1 answer:
AveGali [126]3 years ago
3 0
Y=3x+2
y=3(1.1)+2    substitute value in
y=3.3+2         order of operations: multiply first
y=5.3             then add to get the final answer
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2 (3x+1)=17-3 (x-17)
elena-14-01-66 [18.8K]
<h2>Answer:</h2>

x =  \frac{22}{3}

<h3>alternative form:</h3>

x = 7 \frac{1}{3}  \: or \: x = 7.33333333333

<h2>Step-by-step explanation:</h2>

2(3x + 1) = 17 - 3( x - 17) \\ distribute \\  \\ 6x + 2 = 17 - 3x  + 51 \\ add \: 3x \: from \: both \: sides \\  \\ 9x + 2 = 17  +  51 \\ add \: 17 \: to \: 51 \\  \\ 9x + 2 = 68 \\ subtract \: 2 \: from \: both \: sides \\  \\ 9x = 66 \\  divide \: both \: sides \: by \: 9 \\  \\ x =  \frac{22}{3}

3 0
3 years ago
The graph of the function f(x) = x3 – 7x – 6 intersects the x-axis at the points (–2, 0), (–1, 0), and (3, 0) as shown. Which ex
Alisiya [41]
The x-axis intercepts are the roots of the polynomial. So, the roots are x = - 2, x = - 1 and x = 3.

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5 0
3 years ago
2x-1+3x=0 5x-1=0 how can we get equation b from a
cluponka [151]
2x - 1 + 3x = 0
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7 0
3 years ago
How do you represent any number in an equation?
RideAnS [48]
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5 0
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Which expression is equivalent to 15p^-4q^-6/-20p^-12q^-3 in simplified from? assume p=/ 0,q=/0
enyata [817]
(15p⁺⁴.q⁻⁶) /(-20p⁻¹².q⁻³). 

Remember that  a⁻ⁿ = 1/aⁿ  and 1/a⁻ⁿ = aⁿ


(-15/4).(p⁻⁴.q⁻⁶)(p⁺¹².q⁺³). 

(-15/20).(p⁻⁴.p¹².q⁻⁶.q³)

Remember aⁿ.aˣ = aⁿ⁺ˣ

(-15/20).(p⁸.q⁻³)

-3/5(p⁸.q⁻³)


3 0
3 years ago
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