Which functions have a removeable discontinuity? Check all that apply.
1 answer:
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Answer:
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Step-by-step explanation:
From the diagram, .
The side of the triangle with length 11.9 is adjacent to the given angle.
We also know the hypotenuse to be 14.5 units.
We therefore use the cosine ratio to get;
We take the inverse cosine of both sides to get;
)
Explanation:
A rhombus is a parallelogram in which the diagonals are mutual perpendicular bisectors. The coordinates of the vertices can be used to show ...
- the diagonals bisect each other
- the diagonals are perpendicular
When both these conditions are met, the quadrilateral is a rhombus.
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<h3>Mutual Bisectors</h3>The diagonals will have the same midpoint (bisect each other) if the sum of the coordinates at the ends of one diagonal is the same as the sum of the end point coordinates of the other diagonal:
A +C = B +D
(3, 6) +(9, 6) = (6, 8) +(6, 4)
(3+9, 6 +6) = (6 +6, 8 +4)
(12, 12) = (12, 12) . . . . . . midpoints are the same; ABCD is a parallelogram
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<h3>Perpendicular</h3>The diagonals will be perpendicular if the sum of the products of the coordinate differences of their end points is zero.
AC⋅BD = (C -A)⋅(D -B) = (9 -3, 6 -6)⋅(6 -6, 4 -8)
= (6, 0)⋅(0, -4) . . . . . end point differences; we want their dot-product
= (6)(0) +(0)(-4) = 0 +0 = 0 . . . . diagonals are perpendicular
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<em>Additional comment</em>
The midpoints are computed as (A+C)/2 and (B+D)/2. We have multiplied each of them by 2 to simplify the arithmetic. Our resulting sums of (12, 12) must be divided by 2 to get the actual midpoint of the rhombus: (6, 6).
The notion of "dot product" is a vector notion. Two vectors are perpendicular when their dot product is zero. The dot product is the scalar sum of the products of corresponding coordinates.
