Data set A have a median of 2, mean of 3.4, min of 1 and max of 9. range of 8
Data set B have a median of 7, mean of 6, min of 1 and max of 12, range of 11
so Data set B is much bigger than data set A
Answer:
A.
Step-by-step explanation:
cause its congruent just flip and get
ZYX
brainliest appreciated
Answer:
2p + q = 1
9p + 3q + 3 = 0
q = 1 - 2p
replace q = 1 - 2p into 9p + 3q + 3 = 0
9p + 3(1 - 2p) + 3 = 0
9p + 3 - 6p + 3 = 0
3p + 6 =0
3p = -6
p = -2
q = 1 - 2p
q = 1 -2(-2)
q = 1 + 4
q = 5
(-2 , 5)
there for the answer would be
{(-2, 5)}
Hopefully this was helpful <3 :3
Answer:
5>6
Step-by-step explanation:
Let us calculate the median; the 6th observation is 20, so it is 20. We need the 6th observation so that out of the 11 observations we have 5 above the median and 5 below (or equal). We also have that then Q1 is the median of the lowest 5 observations, hence 19 (14,16,19,19,20, the 3rd observation is 19). Similarly, we get that the median for the upper half of the observations, Q3 namely, is 22 (21,21,22,22,23, the 3rd observation is 22). Thus, the interquartile range is 3=Q3-Q1. According to our calculations, all observations are wrong.
