X, H, and I each have 2 while E has 1.
Answer:
2x^2yz + 3xy^3z - 3xyz^3
Step-by-step explanation:
First you must distribute:
xyz(2x) + xyz(3y^2) + xyz(-3z^2)
Then simplify:
2xyxx + 3xyzy^2 - 3xyz * z^2
And finally simplify each term:
2x^2yz + 3xy^3z - 3xyz^3
I want to help you but please make it easier to understand
