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Bas_tet [7]
3 years ago
6

Find the difference between − 1/6 and − 9/10

Mathematics
1 answer:
MrRa [10]3 years ago
5 0

Answer:

Step-by-step explanation:

-1/6-(-9/10)

=-1/6+9/10

=-\frac{1}{6}+\frac{9}{10}\\=\frac{-5+27}{30}\\=\frac{22}{30}\\=\frac{11}{15}

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Help me asap! I will give you marks
Law Incorporation [45]

Recall the binomial theorem.

(a+b)^n = \displaystyle \sum_{k=0}^n \binom nk a^{n-k} b^k

1. The binomial expansion of \left(1+\frac x3\right)^7 is

\left(1 + \dfrac x3\right)^7 = \displaystyle\sum_{k=0}^7 \binom 7k 1^{7-k} \left(\frac x3\right)^k = \sum_{k=0}^7 \binom 7k \frac{x^k}{3^k}

Observe that

k = 1 \implies \dbinom 71 \left(\dfrac x3\right)^1 = \dfrac73 x

k = 2 \implies \dbinom 72 \left(\dfrac x3\right)^2 = \dfrac73 x^2

When we multiply these by 8-9x,

• 8 and \frac73 x^2 combine to make \frac{56}3 x^2

• -9x and \frac73 x combine to make -\frac{63}3 x^2 = -21x^2

and the sum of these terms is

\dfrac{56}3 x^2 - 21x^2 = \boxed{-\dfrac73 x^2}

2. The binomial expansion is

\left(2a - \dfrac b2\right)^8 = \displaystyle \sum_{k=0}^8 \binom 8k (2a)^{8-k} \left(-\frac b2\right)^k = \sum_{k=0}^8 \binom 8k 2^{8-2k} a^{8-k} b^k

We get the a^6b^2 term when k=2 :

k=2 \implies \dbinom 82 2^{8-2\cdot2} a^{8-2} b^2 = 28 \cdot2^4 a^6 b^2 = \boxed{448} \, a^6b^2

6 0
1 year ago
What multiple of 10 can be used to remove the decimals and fractions in this equation?
dezoksy [38]

Sorry, this was the answer to the wrong question, I'm very sorry for the inconvenience.

8 0
3 years ago
What's 9497÷16 as a whole number and remainder
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Answer:

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Step-by-step explanation:

Hi! If this helped please make this the brainliest answer, I'm on a goal to get 5 brainest answers, thanks!

5 0
4 years ago
Read 2 more answers
Simplify d+n+5d+6n=6n+7
fgiga [73]

Step-by-step explanation:

You can also solve for d instead.

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2 years ago
In ΔDEF, d = 6.4 inches, e = 7.8 inches and ∠F=33°. Find the length of f, to the nearest 10th of an inch.
gogolik [260]

Answer 4.3

Step-by-step explanation:

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4 0
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