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Vlad1618 [11]
3 years ago
5

Write the equation using the slope-intercept form.

Mathematics
1 answer:
dimulka [17.4K]3 years ago
7 0

Answer:

y= -2/3x+9

Step-by-step explanation:

slope int form is y=mx+b, so just take the given numbers and plug them into the equation.

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#4.. are the triangles congruent using SSS Congruence Theorem. Explain
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Yes, the triangles in number 3 are congruent using SSS because all of the sides have the congruent markings.
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3 years ago
If two points of a ray lie in a plane, then all of the ray lies in the plane.true or false
Gnoma [55]
The correct answer for the given statement above would be FALSE. If two points of a ray lie in a plane, then not all of the ray lies in the plane because i<span>f two points of a ray lie in a plane, that does not imply that the ray lies in the plane. If A then B, B does not necessarily imply A. This makes the statement incorrect. </span>
3 0
3 years ago
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Ghella [55]

Answer:

-2/f for the first one, and 1/f is the second one!

7 0
3 years ago
Can someone help me with this problem
Anon25 [30]
Step 1: learn to draw a free-body diagram.  Read your school notes or look up a web site on the subject.
Step 2: Denote the angle of the ramp with the horizontal as theta=tan^(-1)(20/30)=33.69 degrees (approx.)
Step 3: denote the mass of the object as m=100 lb-mass.
Step 4: find force due to mass and gravity = -100g = -100 lb-force. (downwards), denoted by the vector F=(0,-100) lb-force.
Step 5: resolve force along incline:
Force parallel to incline = F1 = -100(cos(theta))
=-83.21 lb-force (negative => down the incline)
Step 6: resolve force perpendicular to incline
= F2 = -100(sin(theta)
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By the way, this question is not calculus 3, but more mechanics, or physics.  You have a better chance of getting answers if posted under "physics".
4 0
3 years ago
Telephone calls arrive at the Global Airline reservation office in Louisville according to a Poisson distribution with a mean of
Lubov Fominskaja [6]

Answer:

The answer is "0.6227 and 0.5971".

Step-by-step explanation:

\to p(x\leq 2)=p(0)+p(1)+p(2)

                  =e^{-2.2}(1+2.2^{1}+\frac{2.2^2}{2!})\\\\=0.6227

\to x \sim emp(\frac{1}{2.2})\\\\\to f(x)=\frac{1}{2.2} emp1-\frac{x}{2.2}

\to p(x \leq 2)=\int^{2}_{0} \frac{1}{2.2} emp1(-\frac{x}{2.2}\ dx

                  =1-emp1-2|2.2\\\\=0.5971

7 0
3 years ago
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