Hello :
the center of this cercle is : O( 0, 0)
calculate the slope m of the line : OA .. A (3,-4)
m= (yA - yO) / (xA- xO)
m = (-4-0)/(3-0)
m= -4/3
if : k the slope of the tangent : k×m = -1 (the tangent perpendiclar of : OA)
k× (-4/3) = -1
k = 3/4
an equation of this tangent is : y - (-4) = (3/4)(x-3)
Answer:
0.5600
Step-by-step explanation:
The thousandths place is lower than 5 so then you round down to the nearest ten.
Answer:
im not 100 percent sure but i think he right
Step-by-step explanation:
Answer:
1. Slope-intercept form: 
Standard form: 
2. Slope-intercept form: 
Standard form: 
3. Slope-intercept form: 
Standard form: 
Step-by-step explanation:
Slope intercept form: 
where:
= y-coordinate
= slope
= x-coordinate
= y-intercept
Standard form: 
Slope-intercept form:
Standard form:
Slope-intercept form:
Standard form:
Slope-intercept form:
Standard form:
Answer:
x=-2
Step-by-step explanation:
1/2(2-6x)-4(x+3/2)=-(x-3)+4
(1-3x)-4x-6=-x+3+4
-7x-5=-x+7
Tranpose
-7x+x=5+7
-6x=12
Divide by -6
x=-2
