Answer:
a. 30 cm³
b. 4.33 g/cm³
Explanation:
a Volume of the object = l*w*h
l = 5 cm
w = 2 cm
h = 3 cm
Volume of object = 5*2*3 = 30 cm³
b. Density of the object = mass of the object / its volume
Mass of object = 130 grams
Volume = 30 cm³
Density of the object = 
Nuclear weapons-15 million K
The populations with the trophic levels that receive the least amount of the total energy from the grass would be Hognose snakes and owls.
<h3>Trophic Level</h3>
The higher we move up a trophic level, the lower the amount of energy transferred from the previous levels.
More precisely put, only about 10% of the total energy available at one trophic level is transferred to the next while the rest is lost as heat to the surrounding.
In this case, Hognose snakes and owls represent the two highest trophic levels in the ecosystem. Thus, their populations would receive the lowest amount of energy from the producer, the grass.
More on energy transfer in trophic levels can be found here: brainly.com/question/13267087
Answer:
Which type(s) of cell division reduce(s) the chromosome number by half?
Meiosis l
Which type(s) of cell division can be classified as reductional?
Meiosis I
Which type(s) of cell division can be classified as equational?
Mitosis and Meiosis II
Explanation:
Meiosis is a type of cell division which occurs in the germ or reproductive cells to produce gametes. It is completed in the two stages, meiosis I and meiosis II. The cells which are going to divide by meiosis are diploid having two sets of chromosomes. Meiosis I is the first stage of the meiosis. At the end of meiosis I two daughter cells are formed having only 1 set of chromosomes and chromosome numbers are reduced to half. Thus, meiosis I is a reductional division.
Mitosis and meiosis II is the equational division as after division chromosome number remains the same as in the parent.
