1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
lara31 [8.8K]
3 years ago
6

If ln(2x=y)=x=1 then dy/dx =

Mathematics
1 answer:
umka21 [38]3 years ago
3 0
N(2x+y) = x +1 

Differentiate both sides, using the Chain Rule on the left side. 
(1 / (2x + y)) * d(2x + y)/dx = 1 
(1 / (2x + y)) * (2 + dy/dx) = 1 

<span>Rearrange to isolate dy/dx.
</span>
You might be interested in
Combine the like terms to create an equivalent expression.<br> 5n - 2n
ValentinkaMS [17]

Answer:

the answer is 3n

Step-by-step explanation:

correct

3 0
3 years ago
Read 2 more answers
F(x) = 3x + x3
____ [38]

Answer:

Please check the explanation.

Step-by-step explanation:

Given

f(x) = 3x + x³

Taking differentiate

\frac{d}{dx}\left(3x+x^3\right)

\mathrm{Apply\:the\:Sum/Difference\:Rule}:\quad \left(f\pm g\right)'=f\:'\pm g'

=\frac{d}{dx}\left(3x\right)+\frac{d}{dx}\left(x^3\right)

solving

\frac{d}{dx}\left(3x\right)

\mathrm{Take\:the\:constant\:out}:\quad \left(a\cdot f\right)'=a\cdot f\:'

=3\frac{d}{dx}\left(x\right)

\mathrm{Apply\:the\:common\:derivative}:\quad \frac{d}{dx}\left(x\right)=1

=3\cdot \:1

=3

now solving

\frac{d}{dx}\left(x^3\right)

\mathrm{Apply\:the\:Power\:Rule}:\quad \frac{d}{dx}\left(x^a\right)=a\cdot x^{a-1}

=3x^{3-1}

=3x^2

Thus, the expression becomes

\frac{d}{dx}\left(3x+x^3\right)=\frac{d}{dx}\left(3x\right)+\frac{d}{dx}\left(x^3\right)

                    =3+3x^2

Thus,

f'(x) = 3 + 3x²

Given that f'(x) = 15

substituting the value  f'(x) = 15 in f'(x) = 3 + 3x²

f'(x) = 3 + 3x²

15 =  3 + 3x²

switch sides

3 + 3x² = 15

3x² = 15-3

3x² = 12

Divide both sides by 3

x² = 4

\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}

x=\sqrt{4},\:x=-\sqrt{4}

x=2,\:x=-2

Thus, the value of x​ will be:

x=2,\:x=-2

5 0
3 years ago
Can you help me please (get brainliest)
marta [7]

9514 1404 393

Answer:

  4/25

Step-by-step explanation:

Put the numbers where the letters are and do the arithmetic.

  \left(2\cdot\dfrac{-1}{2}\cdot\dfrac{2}{5}\right)^2=\left(\dfrac{-2}{5}\right)^2=\dfrac{(-2)^2}{5^2}=\boxed{\dfrac{4}{25}}

6 0
3 years ago
What is the length of the hypotenuse in a right triangle with legs of length 7 and 24?
Fiesta28 [93]
A² + b² = c²   a and b are the legs and c is the hypotenuse.

7² + 24² = c²

49 + 576 = c²

625 = c²

√625 = √c²

25 = c

hope that helps, God bless!

4 0
3 years ago
How do you solve 34.86 x 1.2?
Nezavi [6.7K]

Answer: 41.832

Step-by-step explanation:

I like to write decimals without decimals when multiplying. for this I would do  

3486 x 12 which equals 41832 then You would move the decimal up from 3 spaces from the 2 from 41832 which would put the decimal between the 1 and 8

3 0
3 years ago
Other questions:
  • NEED HELP !!!!!Write an equation for the following proportional relationships. ( x/y ) a. 1/2.5 b . 6/18 C. 5/22.5 d. 4/17​
    14·1 answer
  • What’s the answer for <br> 0.3(12x – 16)<br> a. 3.6x-16<br> b.3.6x-4.8
    7·1 answer
  • Ralph is 3 times as old as Sara. In 6 years , Ralph will be only twice as old as Sara will be then. Find Ralph’s age now .
    8·1 answer
  • Which is greater 17% or 4 over 25?
    8·1 answer
  • The amount of postage placed on a first class letter depends on the weight of the letter .
    12·1 answer
  • Prove With Diagram Which fraction is larger, 5/8 or 3/4 Brainliest
    8·1 answer
  • Find the sum 49+50+51+52+...+141+142
    12·1 answer
  • 5-2(x+2)=12 <br> Decimal Form and work under the problem too HURRY!!!1
    13·1 answer
  • 3=-1.5n<br><br> pls help me (Solving Equations using Multiplication or Division)
    12·2 answers
  • Write the slope intercept equation of a line that has a slope of -3/5 &amp; y-intercept of (0,-4)
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!