Answer:
![P(H](https://tex.z-dn.net/?f=P%28H%20%3C3%29%20%3D%200.875)
Step-by-step explanation:
Given (Missing from the question):
![\begin{array}{cc}{H}&{P(H)&0&0.125&1&0.375&2&0.375&3&0.125\end{array}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Bcc%7D%7BH%7D%26%7BP%28H%29%260%260.125%261%260.375%262%260.375%263%260.125%5Cend%7Barray%7D)
And the required question is:
Determine the P(H < 3)
P(H <3) implies that: P(H = 0) or P(H = 1) or P(H = 2)
So, we have:
![P(H](https://tex.z-dn.net/?f=P%28H%20%3C3%29%20%3D%20P%28H%20%3D%200%29%20%2B%20P%28H%20%3D%201%29%20%2B%20P%28H%20%3D%202%29)
![P(H](https://tex.z-dn.net/?f=P%28H%20%3C3%29%20%3D%200.125%20%2B%200.375%20%2B0.375)
![P(H](https://tex.z-dn.net/?f=P%28H%20%3C3%29%20%3D%200.875)
Answer:
100
Step-by-step explanation:
cut the figure into 2 sides and multiply 8x5 then once you have cut it in half its not 10x12 it is 5x12 you get 40 and 60 then add together to get 100
Answer:
780
Step-by-step explanation:
round up to the nearest ten
Answer:
option (a) It will be closer to 30 than to 20
Step-by-step explanation:
Data provided in the question:
For sample 1:
n₁ = 10
variance, s₁² = 20
For sample 2:
n₂ = 15
variance, s₂² = 30
Now,
The pooled variance is calculated using the formula,
![S^{2}_{p} = \frac{(n_{1}-1)\times s^{2}_{1} +(n_{2}-1)\times s^{2}_{2}}{n_{1}+n_{2}-2}](https://tex.z-dn.net/?f=S%5E%7B2%7D_%7Bp%7D%20%3D%20%5Cfrac%7B%28n_%7B1%7D-1%29%5Ctimes%20s%5E%7B2%7D_%7B1%7D%20%2B%28n_%7B2%7D-1%29%5Ctimes%20s%5E%7B2%7D_%7B2%7D%7D%7Bn_%7B1%7D%2Bn_%7B2%7D-2%7D)
on substituting the given respective values, we get
![S^{2}_{p} = \frac{(10-1)\times 20 +(15-1)\times 30}{10+15-2}](https://tex.z-dn.net/?f=S%5E%7B2%7D_%7Bp%7D%20%3D%20%5Cfrac%7B%2810-1%29%5Ctimes%2020%20%2B%2815-1%29%5Ctimes%2030%7D%7B10%2B15-2%7D)
or
= 26.0869
Hence,
the pooled variance will be closer to 30 than to 20
Therefore,
The correct answer is option (a) It will be closer to 30 than to 20