Answer:9
Step-by-step explanation:
basically what you do is 1equal 1 divided by 8 2 68 equals one so yea
<span>0.5 +x(0.5)
Hope this helped!</span>
Answer:
Step-by-step explanation:
Let the number of cars be x and buses be y
<u>Then we have below inequalities as per given:</u>
- 5x + 32y ≤ 1310
- x + y ≤ 135
It is easy to notice that cars occupy 6 times less area than buses but cost of parking is 3 times less. So we would need maximum number of cars and minimum number of buses to maximize income
<u>Let's assume there are 135 cars and buses, then from the second inequality:</u>
<u>Substitute it in the first one:</u>
- 5(135 - y) + 32y ≤ 1310
- 675 - 5y + 32y ≤ 1310
- 27y ≤ 1310 - 675
- 27y ≤ 635
- y ≤ 635/27
- y≤ 23.5
The greatest number of buses is 23
Option D. 23 is correct
(x+1)(x-4)-(x-2) = 0
x²-4x+x-4-x+2 = 0
x²-4x-2 = 0
/\ = (-4)² - 4*1*(-2)
/\ = 16 + 8
/\ = 24
x = (-(-4)+/- \/24) / 2
x = (4+/-\/4*6)/2
x = (4+/-2\/6)/2
x = 2+/-\/6
x' = 2+\/6
x" = 2-\/6
