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Ainat [17]
3 years ago
12

arjuna has four bills and 11 coins in his wallet. What is the ratio of the number of bills to the number of coins in his wallet?

SAT
2 answers:
Leno4ka [110]3 years ago
8 0

Answer:

4 : 11

Explanation:

You are looking for ration of bills to coins which is

Bills : Coins

The person has 4 bills and 11 coins. So the answer is

4 : 11

Nostrana [21]3 years ago
3 0
Bills to coins
4 : 11
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What are the coefficients for the binomial expansion of (a b)3? 1, 4, 6, 4, 1 1, 1 1, 2, 1 1, 3, 3, 1
Advocard [28]

The coefficients for the binomial expansion of (a + b)³ are 1, 3, 3, 1.

We have,

The binomial expansion (a + b)³,

So,

Now,

We know that,

Formula for binomial expansion,

i.e.

(u + v)ⁿ = ⁿC₀ · uⁿ · v⁰ + ⁿC₁ · uⁿ⁻¹ · v¹ + ⁿC₂ · uⁿ⁻² · v² + ⁿC₃ · uⁿ⁻³ · v³

Now,

According to the question,

Here,

u = a,

v = b,

And, n =3

Now,

Putting values,

i.e.

(a + b)³ = ³C₀ · a³ · b⁰ + ³C₁ · a³⁻¹ · b¹ + ³C₂ · a³⁻² · b² + ³C₃ · a³⁻³ · b³

We get,

(a + b)³ = ³C₀ · a³ · b⁰ + ³C₁ · a² · b¹ + ³C₂ · a¹ · b² + ³C₃ · a⁰ · b³

Now,

Using combination formula,

^{n} C_{r} = \frac{n!}{r!(n-r)!}

On solving we get,

(a + b)³ = a³ + 3 a² b + 3 a b² + b³

So,

Now,

The coefficients of :

a³ = 1,

3a²b = 3,

3ab² = 3,

b³ = 1,

So,

The coefficients of the given binomial expansion are 1, 3, 3, 1.

Hence we can say that the coefficients for the binomial expansion of (a + b)³ are 1, 3, 3, 1.

Learn more about binomial expansion here

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