We are given the following inequality:

If we replace b = 2, we get:

Now we solve for "a" first by subtracting 8 on both sides:

Now we divide both sides by 6

Simplifying:

Therefore, for b = 2, the possible values of "a" are those that are greater than 1/3
B because 6 times 2 is 12...
Answer:
Height = 14.4
Step-by-step explanation:
The diagonals meet at right angles. Interesting property.
The hypotenuse is the side of the rhombus = 15 cm
One of the sides of the small triangles created by the intersection of the diagonals = 24/2 = 12
You can find the other side of the the triangle by using the Pythagorean Theorem
a^2 + b^2 = c^2
c = 15
a = 12
b = ?
12^2 + b^2 = 15^2
144 + b^2 = 225
b^2 = 225 - 144
b^2 = 81
b = 9
The area of this right angle = 9 * 12/2 = 54
There are 4 of them so 4 * 54 = 216
That's the area of the rhombus.
The h= Area / b
b = 15
h = 216/15
h = 14.4
Let angle be x
4 times complement = 4(90 - x)
2/3 times its supplement = 2/3(180 - x)
4(90 - x) = 2/3 (180 - x)
360 - 4x = 120 - 2/3 x
240 = 3 1/3 x
x = 240 / 10/3 = 240 * 3/10 = 72 degrees Answer