For any birth we have only two possible outcomes either boy or girl. So the chance of getting boy or girl on birth same which is 1/2.
The probability of getting baby boy or baby girl on any birth is
P(Boy) = P(Girl) = 0.5
If a couple has six children then probability that all are boys is
P( all six are boy) = (0.5)^6
= 0.015
The probability that all six are boy is 0.015
Answer: 2/3-6=9 is equal to = − 2(2x+6)
- subtract the 12 from both sides so that it becomes the last constant term in the quadratic equation which should now equal 0.
- take the 4x
- half the coefficient of 4 (2)
- square it (4)
- add it to the equation (+4)
- subtract it from the equation (-4)
- factorise the square (x+2)^2 expands to (x^2 + 4x + 2) as {a+b}^2={a^2 + ab + ba + b^2}
- now the equation is in turning point form.
- to find x, add 16 and square root 16 and (x+2)
- subtract 2 from positive or negative 4 (as -4^2 and 4^2 both equal 16).
- This should give you two values for x, -6 and 2.
I really hope that this helped :)
Answer:
x=12
Step-by-step explanation:
First find all possible rational roots. To do this, find all the factors of the lowest order coefficient and the highest order coefficient. For #1, the highest order coefficient is 1 because the x^3 doesn't have a number in front of it. The lowest order coefficient is 30.
Here are all the factors:
Factors of 1 are: 1
Factors of 30 are: 1, 2, 3, 5, 6, 10, 15, 30
Now divide each factor of 30 (positive and negative), and divide them by each factor of 1.
All possible rational roots are:
-1, 1, -2, 2, -3, 3, -5, 5, -5, 6, -10, 10, -15, 15, -30, 30
Now we perform synthetic division like you have started to do. Try dividing the polynomial by each possible root. If the result has a remainder, that possible root does NOT work. Try another possible root. If there is not a remainder, you have found one of the roots.
For example, when dividing x^3 - 4x^2 -11x + 30 by the possible root 2, we get x^2 - 2x - 15 without a remainder. That means 2 is a root. From here we can factor the result to (x-5)(x+3).
So the roots for #1 are x = -3, 2, and 5.
Let me know if you need help with the others :)
