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Katena32 [7]
3 years ago
13

What is the value of x? (1st image)

Mathematics
1 answer:
cluponka [151]3 years ago
8 0
2nd image

Yes, if you rotate it 360 degrees,
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A circle has its center at (1,4) and a radius of 2 units what is the equation of the circle
joja [24]

Answer: x² + y² - 2x - 8y + 13 = 0

Step-by-step explanation:

the equation of the circle is in the form (x - a)² + (y - b)² = r²

where (a,b) is the center of the circle and r is the radius

      hence the equation is

                         (x - 1)² + (y - 4)² = 2²

                         x²-2x+1+y²-8y+16= 4

                         x²+ y² -2x- 8y + 17 =4

                         x² + y² - 2x - 8y = -13

                          x² + y² - 2x - 8y + 13 = 0

3 0
3 years ago
Read 2 more answers
How do I algebraically solve |4x-3|=5√(x+4)
Zepler [3.9K]

Answer:

Step-by-step explanation:

|4x-3|=5√(x+4)  ⇔ |4x-3|²=5²(√(x+4))²  and x+4 ≥ 0

                         ⇔ (4x-3)² = 25(x+4)  and x+4 ≥ 0  ( because : /a/² = a²)

                         ⇔16x²-24x+9 = 25x +100  and x+4 ≥ 0

                         ⇔ 16x² -49x - 91 =0 and x+4 ≥ 0 quadratic equation

Δ = (-49)²-4(16)(-91) = 8225

two solution : X1 = (49-√8225)/32  ≅ - 1.3 accept (-1.3+4 ≥ 0)

                     X2 = (49+√8225)/32  ≅4.37 accept (4.37+4 ≥ 0)

3 0
3 years ago
Please help me asap!​
pickupchik [31]
“d”

you know b cannot work because the x is raised to the x^2 which would be a diff graph

a does not work because -x^3 the graph would be flipped

c is incorrect because the five is in the negative region; not positive
7 0
3 years ago
Help as fast as u can
lyudmila [28]
I believe the answer to your question is going to be

D) g(x)=(x+3)^2

Hope I’m correct!
8 0
3 years ago
Find the Values of the Six Trigonometric Functions for an Angle in Standard Position Given a Point on its Terminal Side
Bezzdna [24]
I think it is -6,6 I am not to sure
3 0
3 years ago
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