Answer: x² + y² - 2x - 8y + 13 = 0
Step-by-step explanation:
the equation of the circle is in the form (x - a)² + (y - b)² = r²
where (a,b) is the center of the circle and r is the radius
hence the equation is
(x - 1)² + (y - 4)² = 2²
x²-2x+1+y²-8y+16= 4
x²+ y² -2x- 8y + 17 =4
x² + y² - 2x - 8y = -13
x² + y² - 2x - 8y + 13 = 0
Answer:
Step-by-step explanation:
|4x-3|=5√(x+4) ⇔ |4x-3|²=5²(√(x+4))² and x+4 ≥ 0
⇔ (4x-3)² = 25(x+4) and x+4 ≥ 0 ( because : /a/² = a²)
⇔16x²-24x+9 = 25x +100 and x+4 ≥ 0
⇔ 16x² -49x - 91 =0 and x+4 ≥ 0 quadratic equation
Δ = (-49)²-4(16)(-91) = 8225
two solution : X1 = (49-√8225)/32 ≅ - 1.3 accept (-1.3+4 ≥ 0)
X2 = (49+√8225)/32 ≅4.37 accept (4.37+4 ≥ 0)
“d”
you know b cannot work because the x is raised to the x^2 which would be a diff graph
a does not work because -x^3 the graph would be flipped
c is incorrect because the five is in the negative region; not positive
I believe the answer to your question is going to be
D) g(x)=(x+3)^2
Hope I’m correct!
