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docker41 [41]
3 years ago
12

Combine like terms to create an equivalent expression. 4\left(1.75y-3.5\right)+1.25y4(1.75y−3.5)+1.25y

Mathematics
2 answers:
sweet-ann [11.9K]3 years ago
4 0

Answer:

<em>8.25y + 14</em>

Step-by-step explanation:

Given the expression

4\left(1.75y-3.5\right)+1.25y

We are to simplify it as shown

Open the parenthesis

4(1.75y) - 4(3.5) + 1.25y

7y - 14 + 1.25y

Collect the like terms

7y + 1.25y - 14

8.25y + 14

<em>Hence the required expression is 8.25y + 14</em>

Jobisdone [24]3 years ago
4 0

Answer:

8.25y−14

Step-by-step explanation:

Use the distributive property to multiply the

4

4start color #ff00af, 4, end color #ff00af into the parentheses.

Hint #22 / 4

4

(

1.75

y

−

3.5

)

+

1.25

y

=4(1.75y−3.5)+1.25yempty space, start color #ff00af, 4, end color #ff00af, left parenthesis, 1, point, 75, y, minus, 3, point, 5, right parenthesis, plus, 1, point, 25, y

=

4

⋅

(

1.75

y

)

+

4

⋅

(

−

3.5

)

+

1.25

y

=4⋅(1.75y)+4⋅(−3.5)+1.25yequals, start color #ff00af, 4, end color #ff00af, dot, left parenthesis, 1, point, 75, y, right parenthesis, plus, start color #ff00af, 4, end color #ff00af, dot, left parenthesis, minus, 3, point, 5, right parenthesis, plus, 1, point, 25, y [Explain]

=

7

y

−

14

+

1.25

y

=7y−14+1.25yequals, 7, y, minus, 14, plus, 1, point, 25, y

Hint #33 / 4

=

7

y

−

14

+

1.25

y

=7y−14+1.25yequals, start color #6495ed, 7, end color #6495ed, y, minus, 14, plus, start color #6495ed, 1, point, 25, end color #6495ed, y

=

(

7

+

1.25

)

y

−

14

=(7+1.25)y−14equals, left parenthesis, start color #6495ed, 7, end color #6495ed, plus, start color #6495ed, 1, point, 25, end color #6495ed, right parenthesis, y, minus, 14 [Explain]

=

8.25

y

−

14

=8.25y−14equals, 8, point, 25, y, minus, 14

Hint #44 / 4

The expanded expression is

8.25

y

−

14

8.25y−14

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wariber [46]

Answer:

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Step-by-step explanation:

Given:

height (h) = 10 in.

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Required:

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6 0
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The indicated function y1(x) is a solution of the given differential equation. Use reduction of order or formula (5) in Section
lisabon 2012 [21]

Answer:

\therefore y_2(x)=-\frac{e^{-6x}}{8}

The general solution is

y=c_1e^{2x}-c_2.\frac{e^{-6x}}{8}

Step-by-step explanation:

Given differential equation is

y''-4y'+4y=0

and y_1(x)=e^{2x}

To find the y_2(x) we are applying the following formula,

y_2(x)=y_1(x)\int \frac{e^{-\int P(x) dx}}{y_1^2(x)} \ dx

The general form of equation is

y''+P(x)y'+Q(x)y=0

Comparing the general form of the differential equation to the given differential equation,

So, P(x)= - 4

\therefore y_2(x)=e^{2x}\int \frac{e^{-\int 4dx}}{(e^{2x})^2}dx

           =e^{2x}\int \frac{e^{-4x}}{e^{4x}}dx

           =e^{2x}\int e^{-4x-4x} \ dx

            =e^{2x}\int e^{-8x} \ dx

            =e^{2x}. \frac{e^{-8x}}{-8}

           =-\frac{e^{-6x}}{8}

\therefore y_2(x)=-\frac{e^{-6x}}{8}

The general solution is

y=c_1e^{2x}-c_2.\frac{e^{-6x}}{8}

4 0
3 years ago
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