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3 years ago

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I NEED ANSWER ASAP!!! PLEASE HELP!!! A shot put is thrown upward with a velocity of 35 ft./sec. at a height of 4 ft. and an angl

e of 40°. How long will it take for the shot put to be a horizontal distance of 40 ft. from the person throwing it? Acceleration due to gravity is 32 ft/s^2. Round your answer to the nearest hundredth.

1 answer:

krek1111 [17]3 years ago

4 0

The horizontal component of the velocity of the shot is 35 cos 40 ft/sec which is constant
Therefore:-
Velocity = distance / time
35 cos 40 = 40 / t

t = = 40 / 35cos40 = 1.49 seconds to nearest hundredth

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