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Katena32 [7]
3 years ago
10

How does having a different strategy to try when you encounter a roadblock help?

Mathematics
1 answer:
UkoKoshka [18]3 years ago
5 0

Answer:

It always helps to have at least one emergency strategy for each subject because it is easy to just lose focus or not be interested. It can help by getting you back on track or solve a problem.

Step-by-step explanation:

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Multiply to remove the variable from the denominator. h= 1/4
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Find the domain and range of y= f() whose graph is given below.<br> (Click on graph to enlarge)
photoshop1234 [79]

Answer:

-8 <_ x < -3

-7 <_ y < -2

Step-by-step explanation:

closed dot means it includes that number so in this case x is least than or equal to -8 and open dot means it doesn't include that value so x is less than -3 and does NOT include -3

and for the y value it's pretty self explanatory if u just count it (i might be off by a little cuz the photo quality is kinda fuzzy but i hope u get the gist!)

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Various problems with data collection can cause some observations to be missing. Suppose a data set has 20 cases. Here are the v
mr Goodwill [35]

Answer:

a) Mean= 15, standard deviation= 5.1575

b) Mean= 15, standard deviation= 3.6469

c) See below

Step-by-step explanation:

(a) Compute the mean and standard deviation for the 10 cases for which x is not missing.

The mean using the ten known values is

\bar x=\frac{17+6+12+14+20+23+9+12+16+21}{10}=15

The standard deviation is

\small s=\sqrt{\frac{(17-15)^2+(6-15)^2+(12-15)^2+(14-15)^2+(20-15)^2+(23-15)^2+(9-15)^2+(12-15)^2+(16-15)^2+(21-15)^2}{10}}=5.1575

(b) Create a new data set with 20 cases by using imputation where you set the values for the 10 missing cases equal to the mean that you computed in the previous part. Compute the mean and standard deviation for this new data set with 20 cases.

The new data set would be

17, 6, 12, 14, 20, 23, 9, 12, 16, 21, 15, 15, 15, 15, 15, 15, 15, 15, 15, 15

The new mean for this set of values would be then

\bar x=\frac{\displaystyle\sum_{i=1}^{20}x_i}{20}=15

The new standard deviation is now

s=\sqrt{\frac{\displaystyle\sum_{i=1}^{20}(x_i-\bar x)^2}{20}}=3.6469

(c) Summarize what you have learned about the possible effects of this type of imputation on the mean and the standard deviation.

Obviously, this way of imputation is somewhat arbitrary and will produce a set of data undoubtedly skewed.  

It could possibly be a sensible way of imputing data if the amount of missing data is very little compared to the whole set, for example one or two data in a set of 100, but in this case we have 50% of missing data and it makes no sense this procedure.

4 0
3 years ago
For all values of x f(x)
Firlakuza [10]

Answer:

f(g(5)) = 64

g(f(5)) = 28

Step-by-step explanation:

Given  that f(x) = x^2 and g(x) = x+3

f(g(x) = f(x+3)

f(x+3) = (x+3)^2

f(g(x)) = (x+3)^2

f(g(5)) = (5+3)^2

f(g(5)) = 8^2

f(g(5)) = 64

b) g(f(x)) = g(x^2)

g(f(x)) = x^2 + 3

g(f(5)) = 5^2 +3

g(f(5)) = 25 + 3

g(f(5)) = 28

Hence the value of g(f(5)) is 28

5 0
3 years ago
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