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Citrus2011 [14]
3 years ago
14

Lan pays a semiannual premium of ​$600

Mathematics
1 answer:
disa [49]3 years ago
4 0

Answer:

$225

Step-by-step explanation:

Automobile = 600

Health insurance = 150 x 12 = 1800

Life insurance = 300

1800 + 300+600 = 2700

2700/12 = $225

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Given this function: f ( x )=−2cos(4 πx ) Find the following:
Neporo4naja [7]

Answer:

Period =½

Equation of midline, y=0

Maximum =2

Minimum=-2

Step-by-step explanation:

The given function is

f(x) =  - 2 \cos(4 \pi \: x)

The period is given by:

\frac{2\pi}{b}  =   \frac{2\pi}{4\pi} =  \frac{1}{2}

The equation of the midline is y=0 since there is no vertical shift

The amplitude of this function is 2 so the range is -2≤y≤2.

Hence the maximum value is 2 and minimum value is -2

4 0
4 years ago
if two straight lines intersect each other in such a way that one of the angles formed measures 90 degree show that each of the
Hitman42 [59]
I hope this helps in answering your question! If you have any inquiries to the solution, feel free to leave a comment!

6 0
4 years ago
Read 2 more answers
What are the zeros of f(x) = x2 + 2x - 80?
Lubov Fominskaja [6]

Answer:

The zeros are 8 and -10, all u have to do is substitute x for those values, factor it, or graph it.

8 0
3 years ago
4(1-x) + 2x = -3( x + 1)
vlada-n [284]

Answer:

x = -7

Solution:

4(1-x) + 2x = -3( x + 1)

4(1 - x) + 2x = -3 (x + 1)

4(-x + 1) + 2x = -3 (x + 1)

-4x - 4 + 2x = -3(x + 1)

-2x + 4 = -3 (x + 1)

8 0
3 years ago
Need help and will be giving Brainliest
Katena32 [7]

Answer:

x-intercept (s):

For this case h (x) = 0

x2 - 2x - 8 = 0

(x-4) * (x + 2) = 0

x1 = 4

x2 = -2

y-intercept:

For this case x = 0

h (0) = (0)2 - 2 (0) - 8

h (0) = - 8

vertex:

We derive the equation:

h '(x) = x2 - 2x - 8

h (x) = 2x - 2

We match zero:

2x-2 = 0

x = 2/2

x = 1

We evaluate the function for x = 1

h (1) = (1)2 - 2 (1) - 8

h (1) = 1 - 2 - 8

h (1) = -9

The vertex is:

(1, -9)

axis of symmetry of the function:

x = 1

Step-by-step explanation:

hope it helps

6 0
3 years ago
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