Ask question

Ask question

All categories

snow_tiger [21]

3 years ago

8

ANSWER PLZ QUICK AND FAST

1 answer:

fomenos3 years ago

5 0

To find out how many Salmon Filet's were served, knowing that 80% of the specials were Salmon Filet, and there were a total of 70 specials in total, we need to find what 80 percent of 70 is. That's because that will lead us to our answer.

Since a percent is something over 100 (per 100), 80% is 80/100 which simplifies to 4/5. That means that we have to multiply 70 by 4/5. 70 * 4/5 is equal to 280/5. Since 280/5 equal 56, there were 56 Salmon Filet's served, or C.

You might be interested in

The dimensions of a rectangle are 3 cm by 5

aleksley [76]

9 or 12 I think Possibly 18

6 0

3 years ago

Read 2 more answers

What are the intercepts of the line? i have a picture of the question and answers could someone please be willing to help?

kati45 [8]

B.) y is vertical x is horizontal (x,y) x meets at -3 and y never touches <span />

4 0

3 years ago

Pls help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

STatiana [176]

The answer to this question is 4v+8
12v+3-6v-9=2v-14+w
12v+3-6v-9-2v+14=w
12v-6v-2v+14-9+3=w
6v-2v+5+3=w
4v+8=w

3 0

4 years ago

Read 2 more answers

Helppppppppppppppp please<br> ty <3 !

ad-work [718]

Answer:

31,547 I used subtraction. I just subtracted 54,927-23,380.

Step-by-step explanation:

54,927

-23,380

------------

31,547

8 0

3 years ago

The manager of a company uses the function shown to model the company’s daily profit based on the price of a product in dollars,

just olya [345]

Answer: 1) The minimum price, in dollars, to avoid a loss = 22,

2) the maximum price in dollars , to avoid a loss = 53,

3) The price that results the maximum profit = 37.5 dollars

Step-by-step explanation:

Since the given function that shows the total profit,

$f(x) = (x-22)(53-x)$

Where x is the price of the product.

Since for avoiding the loss,

$f(x) \geq 0$ ,

⇒ $(x-22)(53-x)\geq 0$

If $(x-22)\geq 0 \implies x\geq 22$

If $53 - x \geq 0 \implies 53 \geq x$

Thus, 53 ≥ x ≥ 22,

Therefore, the minimum price to avoid the loss = $ 22

And, the minimum price to avoid the loss = $ 53

$f'(x) =\frac{d}{dx}[(x-22)(53-x)] = (x-22)\frac{d}{dx} (53-x)+(53-x) \frac{d}{dx}(x-22)$

⇒ $f'(x) = - (x-22)+(53-x) = -x+22+53-x =-2x+75$

Now, For maximum or minimum,

$f'(x) = 0$ ,

⇒ $-2x+75 = 0$

⇒ $-2x = -75$

⇒ $x = 37.5$

$f''(x) = \frac{d}{dx}(-2x+75)=-1$

For x = 37.5, f''(x) is negative,

Thus, For the price of $ 37.5 dollars the company has the greatest profit.

4 0

3 years ago