20.0 + 03.0 + 00.5
,.................
Answer:
idk i kinda forgot what was the answer let me go check
Complete Questions:
Find the probability of selecting none of the correct six integers in a lottery, where the order in which these integers are selected does not matter, from the positive integers not exceeding the given integers.
a. 40
b. 48
c. 56
d. 64
Answer:
a. 0.35
b. 0.43
c. 0.49
d. 0.54
Step-by-step explanation:
(a)
The objective is to find the probability of selecting none of the correct six integers from the positive integers not exceeding 40.
Let s be the sample space of all integer not exceeding 40.
The total number of ways to select 6 numbers from 40 is
.
Let E be the event of selecting none of the correct six integers.
The total number of ways to select the 6 incorrect numbers from 34 numbers is:

Thus, the probability of selecting none of the correct six integers, when the order in which they are selected does rot matter is


Therefore, the probability is 0.35
Check the attached files for additionals
9514 1404 393
Answer:
x +4y = -5
Step-by-step explanation:
The equation of the perpendicular line can be found by swapping the x- and y-coefficients and negating one of them. The new constant can be found by substituting the point values into the equation.
3x +12y = 3(-5) +12(0)
3x +12y = -15
We notice that all of the values include a factor of 3. We can divide that out to put the equation in standard form:
x + 4y = -5