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Radda [10]
4 years ago
5

Dimensions of a house are 500

Mathematics
1 answer:
Olin [163]4 years ago
5 0

Answer:

the answer is 20in. by 5in.

Step-by-step explanation:

you have to divide both of the numbers by 25

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2x-7/3=1 please answer my question iwill mark brainliest
Neporo4naja [7]

2x -  \frac{7}{3}  = 1 \\  \\ 2x = 1 +  \frac{7}{3}  \\  \\ 2x =  \frac{3 + 7}{3}  \\  \\ 2x =  \frac{10}{3}  \\  \\ x =  \frac{5}{3}  \\  \\ x = 1 +  \frac{2}{3}  \\  \\ x = 1 + 0.66666 \\  \\ x = 1.66666

3 0
4 years ago
Read 2 more answers
A college student is interested in investigating the TV-watching habits of her classmates and surveys 20 people on the number of
Alla [95]

Answer:

80% confidence interval of the true average number of hours of TV watched per week is [8.28 hours, 11.02 hours].

Step-by-step explanation:

We are given that a college student is interested in investigating the TV-watching habits of her classmates and surveys 20 people on the number of hours they watch per week. The results are provided below;

<u>Hours of TV per week (X)</u>: 6, 14, 13, 6, 16, 10, 19, 4, 5, 5, 18, 8, 7, 14, 8, 8, 9, 12, 6, 5.

Firstly, the Pivotal quantity for 80% confidence interval for the true average is given by;

                                P.Q. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean number of hours of TV watched per week = \frac{\sum X}{n} = 9.65

            s = sample standard deviation = \sqrt{\frac{\sum (X -\bar X)^{2} }{n-1} }  = 4.61

            n = sample of people = 20

           \mu = true average number of hours of TV watched per week

<em>Here for constructing 80% confidence interval we have used One-sample t-test statistics as we don't know about population standard deviation.</em>

<u>So, 80% confidence interval for the true average, </u>\mu<u> is ;</u>

P(-1.33 < t_1_9 < 1.33) = 0.80  {As the critical value of t at 19 degrees of

                                               freedom are -1.33 & 1.33 with P = 10%}  

P(-1.33 < \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } } < 1.33) = 0.80

P( -1.33 \times {\frac{s}{\sqrt{n} } } < {\bar X-\mu} < 1.33 \times {\frac{s}{\sqrt{n} } } ) = 0.80

P( \bar X-1.33 \times {\frac{s}{\sqrt{n} } } < \mu < \bar X+1.33 \times {\frac{s}{\sqrt{n} } } ) = 0.80

<u>80% confidence interval for</u> \mu = [ \bar X-1.33 \times {\frac{s}{\sqrt{n} } } , \bar X+1.33 \times {\frac{s}{\sqrt{n} } } ]

                                         = [ 9.65-1.33 \times {\frac{4.61}{\sqrt{20} } } , 9.65+1.33 \times {\frac{4.61}{\sqrt{20} } } ]

                                         = [8.28 hours, 11.02 hours]

Therefore, 80% confidence interval of the true average number of hours of TV watched per week is [8.28 hours, 11.02 hours].

7 0
3 years ago
Examine the following typical corporate bond listing:
RoseWind [281]

Answer:

d. 1/8% higher; $1018.75

Step-by-step explanation:

edge21'

good luck, i hope this helps :)

4 0
3 years ago
Read 2 more answers
Find the slope of the line through the pair of points. (-14, -2) and (7,7)
seraphim [82]

Answer:

3/7

Step-by-step explanation:

Use Y2-Y1/X2-X1

So, 7+2/7+14=9/21

9/21 can be simplified so divide both by 3 which leaves you with 3/7

5 0
4 years ago
Which is the right answer
Free_Kalibri [48]

Answer:

2.50

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
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