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crimeas [40]
3 years ago
12

A rectangle is 13 meters longer than it is wide. the perimeter is 98 meters. what is the width?

Mathematics
1 answer:
andrew11 [14]3 years ago
8 0
Hi there!

To solve this problem, let's make two equations:

Let x be the rectangle's length.
Let y be the rectangle's width.

x = y + 13
2x + 2y = 98

Now, since x equals y + 13, we can substitute the value of x into the equation 2x + 2y = 98:

2x + 2y = 98
2(y + 13) + 2y = 98
2y + 26 + 2y = 98
4y = 98 - 26
4y = 72
y = 18

Now, let's plug the value of y into the equation to find x:

x = y + 13
x = 18 + 13
x = 31

So, the length is 31 and the width is 18.

Hope this helps!
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First, let's find the radius. The radius is half of the diameter.

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The perimeter of a kite is 52 meters. If one side measures 19 meters find the measure of the opposite side.
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For any kite, we have two pairs of congruent adjacent sides. In general, the kite would have sides of x, x, y , y. In this case, x = 19 is known while y is unknown.

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