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crimeas [40]
3 years ago
12

A rectangle is 13 meters longer than it is wide. the perimeter is 98 meters. what is the width?

Mathematics
1 answer:
andrew11 [14]3 years ago
8 0
Hi there!

To solve this problem, let's make two equations:

Let x be the rectangle's length.
Let y be the rectangle's width.

x = y + 13
2x + 2y = 98

Now, since x equals y + 13, we can substitute the value of x into the equation 2x + 2y = 98:

2x + 2y = 98
2(y + 13) + 2y = 98
2y + 26 + 2y = 98
4y = 98 - 26
4y = 72
y = 18

Now, let's plug the value of y into the equation to find x:

x = y + 13
x = 18 + 13
x = 31

So, the length is 31 and the width is 18.

Hope this helps!
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Step-by-step explanation:

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5(wx-v)=9(x+v)<br> make x the subject
Zepler [3.9K]
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scZoUnD [109]
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Another way to write an equivalent expression would be to not simplify 7 times the distributed term. You could write 7(-3/4) + 7(-3) which makes #5 correct as well. #5 is 7(-3/4x) - 7(3). If this was simplified, it would equal answer choice 1.

#2 is not correct because 7 times -3/4x does not equal -7 3/4x

#3 is not correct because -21/4 simplifies to -5 1/4, not -6 1/4

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