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Anika [276]
3 years ago
13

Plese help with 11. Tysm means thank you soo much

Mathematics
2 answers:
Natali [406]3 years ago
7 0

Answer:

13/20

Step-by-step explanation:

1/4+2/5=13/20

Solnce55 [7]3 years ago
3 0

Answer:

13/20 lbs

Step-by-step explanation:

1/4 lbs screws + 2/5 lbs nails

We need to get a common denominator

That would be 20

1/4 *5/5 + 2/5 *4/4

5/20 + 8/20

13/20 lbs

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The probability that she gets audited no more than 2 times is 0.896482...

As, a pair of dice are rolling here, so the number of total possible outcome = (6×6) = 36

For Sum = 7 , the favorable outcomes are: (1,6) (2,5) (3,4) (4,3) (5,2) and (6,1)

For Sum = 11 , the favorable outcomes are: (5,6) and (6,5)

For Sum = 12 , the favorable outcome is: (6,6)

Probability = (Number of favorable outcomes)÷(Number of total outcomes)

So, P(7)= \frac{6}{36} =\frac{1}{6}

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P( 7 or 11 or 12) = \frac{1}{6}+\frac{1}{18}+\frac{1}{36} = \frac{6+2+1}{36}=\frac{9}{36} = \frac{1}{4}

Here the total number of trials = 5 and the probability of getting audited = \frac{1}{4}

According the binomial distribution formula:

P(X) = (ⁿCₓ )(P)ˣ (1-P)ⁿ⁻ˣ

where P(X) is the probability of x successes out of n trials

Here, n= 5 and P = 1/4 and we need to find the probability of getting audited no more than 2 times. This means she can gets audited 0, 1 or 2 times.

So,

P(X=0)+P(X=1) +P(X=2)\\\\= [^5C^0 (\frac{1}{4})^0 (1-\frac{1}{4})^5^-^0 ]+[^5C^1 (\frac{1}{4})^1 (\frac{3}{4})^5^-^1]+[^5C^2 (\frac{1}{4})^2 (\frac{3}{4})^5^-^2]\\\\=  (\frac{3}{4})^5+ (5) (\frac{1}{4}) (\frac{3}{4})^4  +(10)(\frac{1}{4})^2 (\frac{3}{4})^3\\\\=0.237304... +0.395507...+0.263671...\\\\ = 0.896482...

So, the probability that she gets audited no more than 2 times is 0.896482...

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How do you solve .05+1.20(0.11-.05)
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Step-by-step explanation:

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Cindy took her cousins to a Hornets game. She spent $180. Twenty percent was for food. How much money was not spent on food
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