A toy rocket lifts off at an initial velocity of 102 feet per second from a height of 10 feet. The height of the rocket can be m odeled by the equation h = – 16t2 + 102t + 10, where ‘t' is the time in seconds. When will the rocket hit to the ground?
1 answer:
Answer:
6.47secs
Step-by-step explanation:
Given the height of the rocket modelled by the equation;
h = – 16t^2 + 102t + 10, where ‘t' is the time in seconds
The rocket will hit the ground at h = 0
Substitute into the equation
– 16t^2 + 102t + 10 = 0
Multiply through by -1
16t^2-102t-10 = 0
t = 102±√(102)²-4(16)(-10)/2(16)
t = 102±√10404+640/32
t = 102±√11044/32
t = 102 ±105.09/32
t = 102+105.09/32
t = 207.09/32
t = 6.47secs
Hence it will take 6.47secs for the rocket to hit the ground
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