Simplifying algebraic expressions 7(-2r+6)
2 answers:
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First you have to find the intercepts!
To find the y-intercept (I usually do that first), pretend x=0.
Then it becomes:
4(0)-3y=12
Which then becomes:
-3y=12.
Divide both sides, and y = -4.
Then the (x,y) coordinate would become (0, -4).
Next you would find the x-intercept, and pretend y = 0.
Which then becomes:
4x-3(0)=12
3x0 cancels out to become:
4x = 12
And x = 3 because division stuffs.
Then THIS point would then be (3,0).
So then, you would plot (0,-4) and (3,0) on a graph and connect the points! I attached a picture for reference.
hope that helped~
To find the y-intercept (I usually do that first), pretend x=0.
Then it becomes:
4(0)-3y=12
Which then becomes:
-3y=12.
Divide both sides, and y = -4.
Then the (x,y) coordinate would become (0, -4).
Next you would find the x-intercept, and pretend y = 0.
Which then becomes:
4x-3(0)=12
3x0 cancels out to become:
4x = 12
And x = 3 because division stuffs.
Then THIS point would then be (3,0).
So then, you would plot (0,-4) and (3,0) on a graph and connect the points! I attached a picture for reference.
hope that helped~
Answer:
Option (D)
Step-by-step explanation:
Coordinates of the points J, E and V are,
J → (-4, -5)
E → (-4, -3)
V → (-1, -1)
This triangle is translated by the rule given in the question.
Coordinates of the image will follow the rule,
(x, y) → [(x + 2), (y + 4)]
following this rule coordinates of the image triangle will be,
J(-4, 5) → J'(-2, -1)
E(-4, -3) → E'(-2, 1)
V(-1, -1) → V'(1, 3)
Therefore, points given in the option (D) will be the answer.