Side of the square: s
Area of the square: As=s^2
Diameter of the circle: d=s
Area of the circle: Ac=pi d^2/4
Ac=pi s^2/4; pi=3.1416
Ac=3.1416 s^2/4
Ac=0.7854 s^2
<span>The likelihood that a point chosen inside the square will also be inside the circle: P=?
P=Ac/As=0.7854 s^2 / s^2
P=0.7854
P=0.7854 * 100%
P=78.54%
</span>The likelihood that a point chosen inside the square will also be inside the circle is 0.7854 or 78.54%
Answer:
i think the answers 5
Step-by-step explanation:
P ( m ) = 0.82
P ( a ) = 0.76
P ( m or a ) = 0.96
P ( m and a ) = ?
--------------------------
P ( m or a ) = P ( m ) + P ( a ) - P ( m and a )
P ( m and a ) = P ( m ) + P ( a ) - P ( m or a ) =
= 0.82 + 0.76 - 0.96 = 0.62
Answer: P ( marinara and alfredo ) = 0.62
F(X)= (6x0) -1
F(x) = 0 -1 = -1
Answer:
3p+2p+8-3=15
5p+5-15=0
5p-10=0
5(p-2)=0
(if you want to solve it p=2)
