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Scorpion4ik [409]
4 years ago
8

Help this is due tomorrow but she didn’t teach us how.

Mathematics
1 answer:
mario62 [17]4 years ago
8 0

Answer:

  see below for drawings and description

Step-by-step explanation:

For geometry problems involving translation, rotation, and reflection—transformations that change location, but not size ("rigid" transformations)—it might be helpful for you to trace the image onto tracing paper or clear plastic so that you can manipulate it in the desired way. Eventually, you'll be able to do this mentally, without the aid of a physical object to play with.

For the images attached here, I copied the triangle onto a piece of clear plastic so I could move it to the desired positions. The result was photographed for your pleasure.

__

a. Translation means the image is moved without changing its orientation or dimensions. You are asked to copy the triangle so that the upper left vertex is moved to what is now point E. See the first attachment.

__

b. Reflection means the points are copied to the same distance on the other side of the point or line of reflection. Just as an object held to a mirror has its reflection also at the mirror, any points on the line of reflection do not move. Reflection flips the image over. See the second attachment.

__

c. Rotation about point D means point D stays where it is. The angle of rotation is the same as the angle at D, so the line DE gets rotated until it aligns with the line DF. The rest of the triangle maintains its shape. See the third attachment.

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Answer:

<h3>The option C) 15 s is correct</h3><h3>Therefore the maximum height it reaches in <u>15 seconds. </u></h3>

Step-by-step explanation:

Given equation is h =-13t^2 + 390t

Given that a projectile is thrown upward so that its distance above the ground after t seconds is h =-13t^2 + 390t

<h3>To find how many seconds does it reach its maximum height:</h3>

"The standard form of a parabola's equation is  expressed as :

y=ax^2+bx+c.

If a>0, then the parabola opens upwards;

if a the parabola opens downwards."

The maximum height is the vertex of the parabola  h =-13t^2 + 390t which is \frac{-b}{2a}.

Comparing the given equation with the standard form of parabola we get

the values of a=-13 , b=390 and c=0

The maximum height in t=\frac{-b}{2a}.

Substitute the values we get

t=-\frac{390}{2(-13)}

=\frac{390}{26}

=15

<h3>∴ t=15 s</h3><h3>∴ The option C) 15 s is correct.</h3><h3>∴ the maximum height is the vertex of the parabola, at t reaches in 15 seconds. </h3>
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