Question

Differentiating Exponential functions In Exercise,find the derivative of the function. See Example 2 and 3.

Answer 1

Answer:

f'(x)$=2(e^4^x)+(x^2+1)(4e^4^x)$

Step-by-step explanation:

The derivative of the function:

$(x^2+1)e^4^x$

The rule for the product of two functions:

f'(x)$=g'(x)h(x)+g(x)h'(x)$

Therefore

g(x)$=x^2+1$

g'(x)$=2$

f(x)$=e^4^x$

f'(x)$=4e^4^x$

f'(x)$=2(e^4^x)+(x^2+1)(4e^4^x)$