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3 years ago

I NEED HELP PLEASE <3

Mathematics

2 answers:

Irina18 [472]3 years ago

6 0

Answer:

8: m= 8x + 4

9: x= weight of Keiko's dog

Step-by-step explanation:

vampirchik [111]3 years ago

4 0

Answer:

8: m= 8x + 4

9: x= weight of Keiko's dog

Step-by-step explanation:

I only know these two. Hope it helps tho <3

You might be interested in

X squared +20 equals 2X

Ivahew [28]

x={1+i√19 , 1-i√19}

solve this by using quadratic formula

5 0

3 years ago

There are 2,100 bacteria in a circular petri dish. The dish has a radius of 40 millimeters. What is the approximate population d

Tems11 [23]

Answer:

B) 0.42

Step-by-step explanation:

population density=number of people/square units

we plug in 2,100 for the first one but we don't know the second one for that we need the area which is A=π $r^{2}$ so the radius is 40 millimeters so $40^{2}$ =1600 1600*π=5024

2,100/5024=0.417 round it up and it is 0.42

so B) 0.42 is the answer

6 0

2 years ago

Perl made the following conjecture.

Travka [436]

Answer:

No, it's not a counterexample, because 48 is a multiple of 8

Step-by-step explanation:

I think like 4 x 3 + 8 x 2 = 28 is a counterexample, because 28 is not a multiple of 8.

7 0

3 years ago

You have made two of the exact same necklaces that cost you a total of $15 in supplies. You have chosen to mark up the price by

tatyana61 [14]

Answer:

A) The selling price for each necklaces is $8.625

B) The profit mark in each necklaces is 15%

Step-by-step explanation:

Given as :

The total cost of two necklaces = c.p = $15

The markup percentage for the necklaces = m = 15%

Let The selling price for both necklaces = s.p

A ) Now, From markup method

m% = $\dfrac{s.p - c.p}{c.p}$

or, 15% = $\dfrac{s.p - 15}{15}$

or, 15% = $\dfrac{s.p}{15}$ - 1

or, $\dfrac{s.p}{15}$ = 1 + 15%

or, $\dfrac{s.p}{15}$ = 1 + $\dfrac{15}{100}$

or, $\dfrac{s.p}{15}$ = $\dfrac{100 + 15}{100}$

or, $\dfrac{s.p}{15}$ = $\dfrac{115}{100}$

∴ s.p = $\frac{15\times 115}{100}$

I.e s.p = $17.25

So, selling price of two necklaces = s.p = $17.25

or, selling price of one necklaces = s.p = $\dfrac{17.25}{2}$ = $8.625

Hence, The selling price for each necklaces is $8.625

Now, Again

B) ∵ The total cost of two necklaces = c.p = $15

So, The cost price of one necklaces = $\dfrac{15}{2}$ = $7.5

∴ profit% for each necklace = $\dfrac{s.p - c.p}{c.p}$

i.e profit% for each necklace = $\dfrac{8.625 - 7.5}{7.5}$

Or, profit% for each necklace = $\dfrac{1.125}{7.5}$

Or, profit% for each necklace = 0.15

So, The profit make in each necklaces = 15%

Hence, The profit mark in each necklaces is 15%

Answer

8 0

3 years ago

The table below shows the number of cars Jing sold each month last year.

ella [17]

Answer:

The median of the data in the table is 19.

Step-by-step explanation:

We are given the following data that shows the number of cars Jing sold each month last year below;

Number of cars Jing sold: 13, 16, 19, 20.5, 23.5

For calculating the median, firstly we have to observe that the number of observations (n) in our data is even or odd because;

If n is odd, then the formula for calculating median is given by;

Median = $(\frac{n+1}{2} )^{th} \text{ obs.}$

If n is even, then the formula for calculating median is given by;

Median = $\frac{(\frac{n}{2} )^{th} \text{ obs.} + (\frac{n}{2}+1 )^{th} \text{ obs.} }{2}$

Here, the number of observations in our data is odd, i.e. n = 5.

So, Median = $(\frac{n+1}{2} )^{th} \text{ obs.}$

= $(\frac{5+1}{2} )^{th} \text{ obs.}$

= $(\frac{6}{2} )^{th} \text{ obs.}$

= 3rd obs. = 19

Hence, the median of the data in the table is 19.

7 0

3 years ago