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Finger [1]
4 years ago
13

Is 2.799 greater than 2.79 ?

Mathematics
1 answer:
BlackZzzverrR [31]4 years ago
6 0
Yes because 2.799 has a extra digit but if there is an answer that they can be the same then they are the same
You might be interested in
Find the slope of a line that includes the points (1,-2) and (2,0)
kvv77 [185]

Answer:slope is 2 or 2/1 whichever way you choose to write it, it’s the same thing

Step-by-step explanation:

8 0
3 years ago
When Emily was born, she weighed 8.2 pounds. Two months later she weighed 10.15 pounds. How much weight did Emily gain in two mo
stiv31 [10]
Hey there! Hello!

The easiest way to solve this problem is by subtracting one value from the other. In order to find how much weight Emily gained in two months, we need to find the difference between her initial weight and how much she weighed at the end of two months:

10.15-8.20=1.95

You can see that I added a zero onto the end of the 8.2. This just evens out the amount of numbers and makes the problem easier to visualize while keeping the amount the same.

From the result of the problem, Emily gained 1.95 pounds in two months. 

I hope this helped you out! Feel free to ask me any additional questions if you have any. :-)
8 0
4 years ago
Read 2 more answers
What is bigger 3/4 or 11/16 and why?
Artist 52 [7]
11/16 is bigger because you can just compare them together and see what will be the answer I just do that when I get a hard Answer
8 0
4 years ago
Read 2 more answers
8 - (-9) simplified with each expression
Arte-miy333 [17]

Hi :)

Let's remember some arithmetic w/ negative integers :

a+(-b)=a-b

a-(-b)=a-b

Now

8-(-9)=8+9=17

So the answer's 17

I hope this helps

7 0
2 years ago
What is this I need the answer
Archy [21]
<h3>Answer is  0</h3>

===========================================================

Explanation:

Logarithms are used to solve exponential equations. Specifically if you have a variable in the exponent, then you use a log to isolate the variable.

If we set the given log expression to x, then we can rewrite it into 8^x = 1. The only value of x that works is x = 0.

------------

Or put another way,

8^x = 1

8^x = 8^0 ... replace the 1 with 8^0

x = 0 ... the bases are equal (to 8) so the exponents must be equal

------------

You can use the change of base formula to directly calculate this log

\log_8(1) = \frac{\log(1)}{\log(8)} = \frac{0}{0.903} = 0

8 0
3 years ago
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