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3 years ago

Please explain the solution for this problem.

Mathematics

1 answer:

inn [45]3 years ago

4 0

Answer:

1st add 2x+25 then 3x+1 then 5x-2 what answer you get thats the answer of this question......

pleae follow me and give me a thanks also mark me brai liest. i will mark u too.....

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4.139 To The Nearest Hundredth

jonny [76]

<span>4.139 To The Nearest Hundredth
= 4.14

hope it helps</span>

3 0

3 years ago

Read 2 more answers

Find the absolute minimum and absolute maximum values of f on the given interval. f(x) = (x2 − 1)3, [−1, 2]

Alja [10]

Given :

$F(x)=3(x^2-1)$

To Find :

the absolute minimum and absolute maximum values of f on the given interval

[-1,2] .

Solution :

Now , getting first order differential equation and equating its equal to zero.

$\dfrac{d(3x^2-3)}{dx}=0\\\\6x=0\\x=0$

So , x=0 is critical point .

Now , coefficient of $x^2$ is positive .

Therefore , it is increasing function after x=0 .

So , min value will be at , x=0.

$Min = (0^2-1)\times 3=-3$

And maximum value will be the maximum at the x=2 because it is increasing function .

$Max=(2^2-1)\times 3=9$

Therefore , max and min value is 9 and -3 respectively .

Hence , this is the required solution .

3 0

3 years ago

A random sample of 25 fields of spring wheat has a mean yield of 27.6 bushels per acre and standard deviation of 5.69 bushels pe

ale4655 [162]

Answer:

Step 1 z(c) = 2,323

CI = ( 25 ; 30,2 )

Step-by-step explanation:

Normal Distribution:

Sample size n = 25

Sample mean μ = 27,6

Sample standard deviation s = 5,69

CI = 98 % then α = 1 - 0,98 α = 0,02 α/2 = 0,01

From z-table we don´t find z (score) for 0,01 directly, we need to interpolate between z = 2,32 and z = 2,33

For 0,0099 z score is 2,33

for 0,0102 z score is 2,32

Δ 0,0003 0,01

Then by rule of three

for Δ 0,0003 ⇒ 0,01

for Δ (0,01- 0,0102) ⇒ x

0,0003 0,01

0,0002 x

x = 0,0067

then z (score for 0,01) = 2,33 - 0,0067 z(c) = 2,3233

round to three decimal places z(c) = 2,323

Step 2:

CI = μ ± z(c) * s/√n ⇒ 27,6 ± (2,323 * 5,69)/5

CI = 27,6 ± 2,6436

round to one decimal place

CI = 27,6 ± 2,6

CI = ( 25 ; 30,2 )

8 0

3 years ago

Given: cosθ= -4/5 , sin x = -12/13 , θ is in the third quadrant, and x is in the fourth quadrant; evaluate tan 1/2 θ

mrs_skeptik [129]

Answer:

Step-by-step explanation:

If you're looking for what the half angle of the tangent of theta is, I'm a bit confused as to why you think the angle in the 4th quadrant, x, is relevant. But maybe you don't know it isn't and it's a "trick" to throw you off. Hmm...

Anyways, the half angle identity for tangent is

$tan(\frac{\theta}{2})=\frac{sin\theta}{1+cos\theta}$

There are actually 3 identities for the tangent of a half angle, but this one works just as well as either of the others do, so I'm going with this one.

If theta is in QIII, the value of -4 goes along the x axis and the hypotenuse is 5. That makes the missing side, by Pythagorean's Theorem, -3. Filling in our formula:

$tan(\frac{\theta}{2})=\frac{-\frac{3}{5} }{1+(-\frac{4}{5}) }$ which simplifies a bit to