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3 years ago

Please explain the solution for this problem.

Mathematics

1 answer:

inn [45]3 years ago

4 0

Answer:

1st add 2x+25 then 3x+1 then 5x-2 what answer you get thats the answer of this question......

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<img src="https://tex.z-dn.net/?f=f%28x%29%20%3D%20%20%5Csqrt%7Bx%7D%20" id="TexFormula1" title="f(x) = \sqrt{x} " alt="f(x) =

Georgia [21]

Answer: $\dfrac{1}{2\sqrt x}$

<u>Step-by-step explanation:</u>

$\lim_{h \to 0} f(x)=\dfrac{f(x+h)-f(x)}{h}$

f(x) = $\sqrt x\\$

f(x+h) = $\sqrt{x+h}$

$\lim_{h \to 0} f(x)=\dfrac{\sqrt{x+h}-\sqrt x}{h}$

$=\dfrac{\sqrt{x+h}-\sqrt x}{h}\bigg(\dfrac{\sqrt{x+h}+\sqrt x}{\sqrt{x+h}+\sqrt x}\bigg)$

$=\dfrac{(x + h)-(x)}{h(\sqrt{x+h}+\sqrt x)}$

$=\dfrac{h}{h(\sqrt{x+h}+\sqrt x)}$

$=\dfrac{1}{\sqrt{x+h}+\sqrt x}$

$=\dfrac{1}{\sqrt{x+0}+\sqrt x}$

$=\dfrac{1}{2\sqrt x}$

4 0

3 years ago

Could someone answer this for me please? thanks:)) id appreciate it

KIM [24]

Answer:

Not sure but I think the answer is No.1

6 0

3 years ago

Nine times the sum of a number and three find the equation

Artyom0805 [142]

Answer:

9 x n + 3

Step-by-step explanation:

3 0

3 years ago

The pool holds 15069 of water and is leaking at a rate of 4 gallons per day how many gallons will remain in the pool after 141 d

Veronika [31]

Answer:

Water remaining in the pool after 141 days = 14,505 gallons

Step-by-step explanation:

Total number of gallons of water in the pool = 15,069

Rate of leakage of water = 4 gallons per day

Using unitary method

1 day leakage of water from the pool = 4 gallons

∴ In 141 days leakage of water from the pool will be = $141\times4=564$ gallons

After leaking 564 gallons of water, total gallons of water that will remain in the pool will be = $15,069-564=14,505$ gallons

8 0

3 years ago

Factor this equation <br> 4x-16

DaniilM [7]

4(x-4)

Factor out 4 from both terms.

6 0

3 years ago

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Please explain the solution for this problem.​

Please explain the solution for this problem.