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ludmilkaskok [199]
3 years ago
9

I need help on this.

Mathematics
2 answers:
Blababa [14]3 years ago
8 0
This is true. On a parallelogram, adjacent sides intersect and opposite sides are parallel.
valentinak56 [21]3 years ago
3 0

Answer: True

The opposite sides of a parallelogram are congruent or equal in length. The opposite sides are also parallel. It might help to think of a rectangle, which is a special case of a parallelogram.

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Please help me answer the question in the picture
Genrish500 [490]
$338 / 2 = $169

A = a^2 = 169
a= 13

answer
13ft
6 0
3 years ago
Read 2 more answers
Find the vertex of this parabola:<br> y = -2x2 + 4x - 10
amm1812
The parabola equation in its vertex form is y = a(x-h)² + k , where:
a is the same as the a coefficient in the standard form;
h is the x-coordinate of the parabola vertex; and.
k is the y-coordinate of the parabola vertex.
that’s how you find it
3 0
3 years ago
What is equal to 0/0<br><br> 0<br> 0<br> 0<br> none of the above
babunello [35]

Answer:

well um I have to go with 0

6 0
3 years ago
Aşağıda verilen balik kılçığı diyagramını tamamlayalım.<br>​
oee [108]

Answer:  

Let's complete the fishbone diagram given below

thats  what they said

Step-by-step explanation:

8 0
2 years ago
Two people start from the same point. One walks east at 4 mi/h and the other walks northeast at 8 mi/h. How fast is the distance
kvasek [131]

Answer:

5.89 mi/h

Step-by-step explanation:

This problem can be solved by using different methods. I will use vectors since it's the simplest way in which we can solve it. This can be solved by using related rates of change though.

First, we start by drawing a diagram with the velocity vectors.

A= velocity of the first person

B= velocity of the second person

C= velocity in which they are moving away from each other.

Since there is no acceleration in the problem, we can suppose we are talking about constant speeds, so the velocity at which they are moving away from each other will always remain constant. (It doesn't matter what time it is, the velocity will always be the same)

Having said this we can solve this problem by using the components, by using law of cosines or graphically. I will use law of cosines. The idea is to find the length of side c.

Law of cosines:

C^{2}=A^{2}+B^{2}-2ABcos \gamma

so we can solve the formula for C so we get:

C=\sqrt{A^{2}+B^{2}-2ABcos \gamma}

and now we can substitute the values we know:

C=\sqrt{(4)^{2}+(8)^{2}-2(4)(8)cos 45^{o}}

C=\sqrt{16+64-32\sqrt{2}}

C=\sqrt{80-32\sqrt{2}} mph

if we want an exact answer, then that will be the exact answer, which approximates to:

C=5.89 mph

4 0
3 years ago
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